91Ó°ÊÓ

The given data is listed below,

The dipole moment of the HF (hydrogen fluoride) is,$\mathrm{p}=6.3×{10}^{-30}\mathrm{C}â‹\dots \mathrm{m}$

The dipole moment is described as the measurement of two opposite charges’ separation. The dipole moment is described as the product of the charge of the electron and the separation between molecules.

The concept of the dipole moment gives the separation between H and F.

The expression for the dipole moment is as follows,

$p=qs$

Here, p is the dipole moment, q is the charge on the electron and its value is $1.6×{10}^{-19}\mathrm{C}$, s is the separation between H and F .

Substitute $6.3×{10}^{-30}\mathrm{C}â‹\dots \mathrm{m}\mathrm{for}\mathrm{p},\mathrm{and}1.6×{10}^{-19}\mathrm{C}\mathrm{for}\mathrm{q}.$

This is not plausible as the separation between Hand F ion is $\mathrm{s}=3.937×{10}^{-11} \mathrm{m}$which is $≈ 40\mathrm{picometer}$which is nearly half the value of s , the actual value of separation between H and F ion is about $91.7\mathrm{picometer}.$

Thus, the separation between H and F isrole="math" localid="1656930521340" $\mathrm{s}=3.937×{10}^{-11} \mathrm{m}$ and it is not plausible.