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Consider the situation in Figure 13.39. (a) If we double the distance d, by what factor is the force on the point charge due to the dipole reduced? (b) How would the magnitude of the force change if the point charge had a charge of +3Q? (c) If the charge of the point charge were -2Q, how would the force change?

Short Answer

Expert verified
  1. The force on the point charge due to the dipole reduced by a factor equal to 18.
  2. The factor by which the electric force increases if the point charge has a charge of +3Q is3.
  3. The factor by which the magnitude of the electric force changes if the point charge has a charge of -2Q is 2.

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • The changed value of the distance is, d1=2d.
  • The magnitude of new point charge is +3Q.
  • The magnitude of another new changed point charge is -2Q.
02

Significance of electric dipole

Whenever the interaction of a specific point charge with an electric dipole occurs, there would be an electric force due to the electric dipole acting on the point charge.

03

Determination of the force on the point charge due to the dipole reduced by double the distance. Part (a)

The electric field due to the dipole at the location of the point charge points in the -x direction and the expression of the dipole exerts a force on toward the dipole can be expressed as,

F→=QE→=Q-14πε02qsd3,0,0.....(1)

Here,F→ represents the dipole exerts a force on Q toward the dipole,E→ represents the electric field due to the dipole at the location of the point charge points in the -x direction,ε0 represents the vacuum permittivity.

Now since the distance doubles then the expression of the dipole exerts a force on Q toward the dipole can be expressed as,

F1→=Q-14πε02qsd13,0,0

Here,F1→ represents the dipole exerts a force on Q toward the dipole due to double the distance d.

Substitute all the values in the above equation.

F1→=Q-14πε02qs2d3,0,0=18Q-14πε02qsd3,0,0=18F→

Hence, the electric force on the point charge due to the dipole reduced by a factor equal to 18.

04

Determination magnitude of the force change if the point charge had a charge of +3Q. Part (b)

Now since the magnitude of the point charge changes to +3Q then the expression of the dipole exerts a force on +3Q toward the dipole can be expressed as,

F2→=+3Q-14πε02qsd3,0,0....2

Here, F2→represents the dipole exerts a force on +3Q toward the dipole.

On solving the equation (1) and equation (2) we get:

F2→=+3Q-14πε02qsd3,0,0=3F→

Hence, the factor by which the electric force changes if the point charge has a charge of +3Q is 3.

05

Determination magnitude of the force change if the point charge had a charge of -2Q. Part (c)

Now since the magnitude of the point charge changes to -2Q then the expression of the dipole exerts a force on -2Q toward the dipole can be expressed as,

F3→=-2Q-14πε02qsd3,0,0....3

Here,F3→ represents the dipole exerts a force on -2Q toward the dipole.

On solving the equation (1) and equation (3) we get:

F3→=-2Q-14πε02qsd3,0,0=2F→

Hence, the factor by which the magnitude of the electric force changes if the point charge has a charge of -2Q is 2.

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