91Ó°ÊÓ

The drift speed of electron current in a copper wire is,$v_d=7×{10}^{-5}\frac{m}{s}$.

The mobility of mobile electrons in copper is, $Mobility=4.5×{10}^{-3}\frac{\left({\displaystyle \frac{m}{s}}\right)}{\left({\displaystyle \frac{N}{C}}\right)}$.

Consider a current is supplied to a conducting material then the current travels in form of free electrons. The speed of free electrons inside a conducting material is described as the drift speed of electrons.

The drift speed of the electrons inside a conducting material relies upon the mobility of the free electrons and the electric field in the conducting material

The formula for the mobility of mobile electrons in copper is as follows:

$$\begin{gathered} Mobility=\frac{v_d}{E} \\ E=\frac{v_d}{Mobility} \end{gathered}$$

Substitute the values and solve as:

$$\begin{gathered} E=\frac{7×{10}^{-5}{\displaystyle \frac{m}{s}}}{4.5×{10}^{-3}{\displaystyle \frac{\left({\displaystyle \frac{m}{s}}\right)}{\left({\displaystyle \frac{N}{C}}\right)}}} \\ E=1.556×{10}^{-8}\frac{N}{C} \end{gathered}$$

Hence, the magnitude of the electric field inside the copper wire is$1.556×{10}^{-8}\frac{N}{C}$$1.556×{10}^{-8}\frac{N}{C}$.