91Ó°ÊÓ

Mass of climber hanging from the rope in the first case = 55 kg.

Mass of climber hanging from the rope in the first case = 88 kg.

The tension in a rope when a massMhangs motionless in it can be written as,

T=Mg (I)

Here gthe acceleration due to gravity of value is given as,

$\mathbf{g}\mathbf{=}\mathbf{9}\mathbf{.}\mathbf{8}\mathbf{}\mathbf{m}\mathbf{/}{\mathbf{s}}^{\mathbf{2}}$

a)

From equation (I), the tension in the rope in the first case can be calculated as,

$\begin{array}{rcl}\mathrm{T}& =& 55\mathrm{kg}×9.8\mathrm{m}/{\mathrm{s}}^2\\ & =& 539.\left(1\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2×\frac{1\mathrm{N}}{1\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2}\right)\\ & =& 539\mathrm{N}\end{array}$

Thus, the tension is 539 N.

b)

From equation (I), the tension in the rope in the second case can be calculated as,

$\begin{array}{rcl}\mathrm{T}& =& 88\mathrm{kg}×9.8\mathrm{m}/{\mathrm{s}}^2\\ & =& 862.4.\left(1\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2×\frac{1\mathrm{N}}{1\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2}\right)\\ & =& 862.4\mathrm{N}\end{array}$

Thus, the tension is 862.4 N.

As obtained above, the tension in the rope is different in the two cases. In the second case, more force is applied to the rope, which increases the interatomic distance of the rope.

Thus, (2) the interatomic bonds in the rope are stretched more when the rope supports the heavier climber than when the rope supports the lighter climber is correct.