91影视

The distance between the plates of the capacitor is increased when capacitor is completely charged.

The capacitance of the capacitor is given by the ratio of the product of area of plates and permeability of space and spacing between the plates.

The expression to calculate the value of the capacitor is given as follows

$\mathit{C}\mathbf{=}\frac{\mathbf{A}{\mathbf{蔚}}_{\mathbf{0}}}{\mathbf{d}}$

Here, is the spacing between the plates, is the area of plates and is the permeability of the space.

The initial value of the capacitance is given by,

$C_1=\frac{A{蔚}_0}{d_1}$ 鈥︹�� (i)

Here, is the initial distance between the plates.

Consider the circuit given below in which the direction of the conventional current is shown by the arrows.

Let鈥檚 assume the plates are separated by the new spacing . The capacitance is given by,

$C_2=\frac{A{蔚}_0}{d_2}$ 鈥︹�� (ii)

Here, $d_2$is the new distance between the plates.

From equations (i) and (ii), it is clear that the capacitance is inversely proportional to the spacing between the plates.

The capacitor plates move away, and the distance between plates increases, reducing capacitance. Since in both cases, capacitance is connected with the same voltage, due to which the current flows back to the power supply to restore the voltage.

Therefore, the current starts to flow in the reverse direction, and the arrows show the direction of the conventional current.

Hence when the spacing between the plates is increases the capacitance reduces and direction of the current get reversed.