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In statistical mechanics, we frequently use the approximationN! = N In N-N, where N is of the order of Avogadro’s number. Write out ln N! using Stirling’s formula, compute the approximate value of each term for N = 1023 , and so justify this commonly used approximation.

Short Answer

Expert verified

The approximation is justified.

Step by step solution

01

Given Information

The approximation is N! =N InN- N .

02

Definition of the sterling’s formula.

Sterling’s formula is used to simplify formulas involving factorial.

n!â–¡nne-n2Ï€²Ô.

03

Justify the approximation.

The approximation is N! = N In N - N.

The sterling’s formula is n!â–¡nne-n2Ï€²Ô.

Take log on both side on the formula mentioned above.

The equation becomes as follows.

Inn!=Innne-n2Ï€²Ô1+112n=Innn+Ine-n+Inn+In1+112n=nInn-n+12Inn+In1+112n

Substitute n = 1023 in the above equation.

The equation becomes as follows.

nInn=5.526×1026where,n=1023Inn=55In1+112n≈0

Hence, In(n!) = nIn n - n .

The approximation is justified.

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