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In Problem 4 to 13, identify each of the integral as an elliptic (see Example 1 and 2). Learn the notation of your computer program (see Problem 3) and then evaluate the integral by computer.

8. ∫03249-4t21-t2dt

Short Answer

Expert verified

The value of integral in elliptic form is 7E32,27≈6.11662.

Step by step solution

01

Given Information

The value of integration is ∫03249-4t21-t2dt.

02

Definition of elliptic form

The elliptic form of the integral is defined as E(1,k)=∫011-k2t21-t2dt.

03

Find the value of Integral

The value of integration is ∫03249-4t21-t2dt.

Factor out 49 the equation becomes as follows,

l=∫032491-4t2491-t2dt=7∫0321-4t2491-t2dt

The formula for the beta function is E1,K=∫011-k2t21-t2dt.

Equate the above equation with the value of I, the value of I becomes follows.

l=7∫0321+22t2721-t2dtl=7E32,27l≈6.11662

Hence, the solution is mentioned below.

The value of integral in elliptic form is 7E32,27≈6.11662.

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