/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10.6P The logarithmic integral is li(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The logarithmic integralis li(x)=∫0xdtInt. Express as exponential integrals

  1. li(x)
  2. li(ex)
  3. li(x)=∫0xdtIn(1t)

Short Answer

Expert verified

The following required expressions are shown:

  1. lix=EiInx
  2. liex=Eix
  3. =-EiInx

Step by step solution

01

Given information

The definition of a logarithmic integral is given.

li(x)=∫0xdtInt

02

Begin with making a substitution.

(a)

Make the following substitution.

t=eudt=eudu

Apply the substitution in the given integrand.

lix=∫-∞Inxeuudu=EiInx

03

Substitute the values in the domain.

(b)

Substitute ex in the domain of li(x).

liex=∫-∞xeuudu=Eix

04

Repeat the process.

(c)

Use the following substitution.

t=eudt=eudu

Apply the substitution in the given integrand.

∫-∞Inxeu-udu=∫Inx-∞euudu=-EiInx

Thus, the following expressions are shown:

(a)li(x)=Ei(Inx)(b)li(ex)=Ei(x)(c)=-Ei(Inx)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the pendulum problem, θ=αsinglt is an approximate solution when the amplitude α is small enough for the motion to be considered simple harmonic. Show that the corresponding exact solution when α is not small issinθ2=sinα2snglt,k=sin(α2) is the modulus of the elliptic function. Show that this reduces to the simple harmonic motion solution for small amplitude α

Replace x by ix in (9.1) and let t = iuto show that erf(ix) = ierfi(x), where erfi(x) is defined in (9.7).

Without computer or tables, but just using facts you know, sketch a quick rough graph of the Γfunction from -2to 3. Hint:This is easy; don’t make a big job of it. From Section 3, you know the values of the data-custom-editor="chemistry" Γfunction at the positive integers in terms of factorials. From Problem 1, you can easily find and plot the Γfunction at ±1/2, ±3/2. (Approximateas a little less than 2.) From (4.1) and the discussion following it, you know that the Γfunction tends to plus or minus infinity at 0 and the negative integers, and you know the intervals where it is positive or negative. After sketching your graph, make a computer plot of the Γ function from -5to 5and compare your sketch.

Express the following integrals as β functions, and then, by (7.1) , in terms of Γ functions. When possible, use Γfunction formulas to write an exact answer in terms of π,2 , etc. Compare your answers with computer results and reconcile any discrepancies.

role="math" localid="1664349717981" ∫01x41-x2dx

Sketch or computer plot a graph of the function y=e-x2 .

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.