Chapter 1: Problem 37
The dimensions of electrical conductivity are (a) \(\left[\mathrm{ML}^{3} \mathrm{~T}^{-3} \mathrm{~A}^{-2}\right]\) (b) \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{3} \mathrm{~A}^{2}\right]\) (c) \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{3} \mathrm{~A}^{2}\right]\) (d) \(\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{-3} \mathrm{~A}^{2}\right]\)
Short Answer
Step by step solution
Understand Electrical Conductivity
Determine Dimensions of Resistivity
Calculate the Dimensions of Conductivity
Simplify the Dimensions
Match the Final Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrical Conductivity
Resistivity
- The dimensions of electric field \( E \) are \([MLT^{-3}A^{-1}]\).
- The dimensions of current density \( J \) are \([L^{-2}A]\).
Electric Field
- Electric fields are measured in newtons per coulomb (N/C) or volts per meter (V/m).
- The dimensional formula for electric field \( E \) is \([MLT^{-3}A^{-1}]\).
Current Density
- Represented by \( J \), it is calculated as the current \( I \) over the area \( A \) as \( J = \frac{I}{A} \).
- The dimensional formula for current density is \([L^{-2}A]\).
Physics JEE Main
- Dimensional analysis simplifies understanding and solving physics problems by ensuring units align correctly.
- It is particularly useful in examinations like JEE Main, where quick thinking and verification of solutions can lead to time efficiency and accuracy.