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The time dependence of a physical quantity \(P\) is given by \(P=P_{0} e^{-a t^{2}}\), where \(\alpha\) is a constant and \(t\) is time. Then constant \(\alpha\) is (a) dimensionless (b) dimension of \(t^{-2}\) (c) dimensions of \(\boldsymbol{P}\) (d) dimension of \(t^{2}\)

Short Answer

Expert verified
The dimension of \( \alpha \) is \( t^{-2} \), so the answer is (b).

Step by step solution

01

Understanding the Equation

The physical quantity is given as a function of time: \( P = P_0 e^{-\alpha t^2} \). Here, \( P_0 \) is the initial value of \( P \), \( \alpha \) is a constant, and \( t \) is time.
02

Analyzing the Exponential Term

The term \( e^{-\alpha t^2} \) is an exponential function. In exponential functions of the form \( e^x \), the exponent \( x \) must be dimensionless, meaning it has no physical dimension.
03

Determining Dimensions of \( \alpha \)

Since \( \alpha t^2 \) must be dimensionless, the dimensions of \( \alpha \) must cancel out the dimensions of \( t^2 \). The dimension of time \( t \) is \( T \), so \( t^2 \) has dimensions of \( T^2 \). Hence, \( \alpha \) must have dimensions \( T^{-2} \) to make \( \alpha t^2 \) dimensionless.
04

Verifying the Answer

We conclude that the dimensions of \( \alpha \) should be such that they cancel out with the dimensions of \( t^2 \). This can only happen if \( \alpha \) has dimensions of \( T^{-2} \). Therefore, option (b) is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. They are written as \( e^x \), where \( e \) represents the Euler's number, approximately equal to 2.718. These functions are significant because they model many natural processes such as population growth, radioactive decay, and in this context, the change of a physical quantity over time.
Here, \( P = P_0 e^{-\alpha t^2} \) represents an equation where \( P \) changes exponentially with respect to \( t \), the time. The function \( e^{-\alpha t^2} \) decreases as \( t \) increases, illustrating how the quantity \( P \) diminishes over time in a manner dictated by the constant \( \alpha \). This is typical for processes with a trend towards stabilization or decay.
  • Exponential functions can model both growth (positive exponent) and decay (negative exponent).
  • They are critical in understanding processes that change rapidly and continuously.
Dimensionless Quantities
Dimensionless quantities are values that don't rely on physical units or dimensions to have meaning. They are pure numbers, like ratios, percentages, or indices. In equations involving exponential functions, like \( e^{-\alpha t^2} \), the exponent must be dimensionless. This ensures that the exponential aspect of the function is purely numerical, allowing for a consistent mathematical model.
In our example, \( \alpha t^2 \) must be dimensionless. Since \( t \), time, has dimensions of \( T \), and \( t^2 \) would subsequently have dimensions of \( T^2 \), the constant \( \alpha \) needs the dimension \( T^{-2} \). This cancels out the factor \( T^2 \) from time, leaving the exponent without dimensions.
  • Being dimensionless ensures that the calculation is consistent across different units of measurement.
  • Enables the exponent in the exponential function to be purely a numerical expression.
Time Dependence
Time dependence refers to how a physical quantity changes as time progresses. It's a fundamental concept in physics and mathematics as it helps in predicting and understanding dynamic systems. In the equation \( P = P_0 e^{-\alpha t^2} \), time dependence is explicit. The quantity \( P \) diminishes over the period because \( t^2 \), which increases over time, is directly affecting the rate of change of \( P \).
This kind of dependency shows that the behavior of \( P \) is not constant but varies according to elapsed time, indicative of processes such as cooling, attenuation, or other forms of exponential decay.
  • Time-dependent equations are vital for predicting how systems evolve.
  • Allows for analyzing the transient states before reaching equilibrium.
  • Shows the intrinsic link between time and the dynamic nature of physical quantities.

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Most popular questions from this chapter

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Let \(\left[\varepsilon_{0}\right.\) ] denote the dimensional formula of the perimitivity of vacuum. If \(M=\) mass, \(L=\) length, \(T\) = Time and \(A=\) electric current, then [JEE Main 2013] (a) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{2} \mathrm{~A}\right]\) (b) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{4} \mathrm{~A}^{2}\right]\) (c) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{2} \mathrm{l}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{-2}\right]\) (d) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-} \mathrm{l}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{2}\right]\)

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