/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Which of the following is a unit... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 29

Which of the following is a unit of permeability (a) \(\mathrm{H} / \mathrm{m}\) (b) \(\mathrm{Wb} / \mathrm{Am}\) (c) ohm \(\times \mathrm{s} / \mathrm{m}\) (d) \(\mathrm{V} \times \mathrm{s} / \mathrm{m}^{2}\)

Short Answer

Expert verified
The unit of permeability is H/m, which is option (a).

Step by step solution

01

Identify the Unit of Permeability

Permeability is a measure of how easily a material can support the formation of a magnetic field within itself. The standard unit of permeability in the International System of Units (SI) is the henry per meter (H/m).
02

Analyze Given Options

Review the units provided in options (a) through (d): 1. Option (a) is H/m. 2. Option (b) is Wb/Am. 3. Option (c) is ohm 脳 s/m. 4. Option (d) is V 脳 s/m虏.
03

Match the Correct Unit

Compare each option to the known unit of permeability, H/m. - Option (a) matches exactly as H/m. - Options (b), (c), and (d) do not match the unit for permeability as they represent different physical quantities or combinations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SI Units
The International System of Units, commonly abbreviated as SI, is the modern form of the metric system. It is used worldwide in science and industry to provide consistency and clarity. SI Units help in defining specific and standard measures for every physical quantity.For understanding the concept of magnetic permeability, it's important to know that SI Units play a crucial role. Magnetic permeability, which indicates how well a material can support a magnetic field, is expressed in henry per meter (\(\mathrm{H/m}\)) in SI Units.
  • The basic purpose of SI Units is to provide a universally recognized framework for measurements.
  • By using the same units globally, scientists and engineers can share and compare results with ease.
  • Standardization of units prevents confusion that could result from differing measurement systems.
SI Units ensure that no matter where you are in the world, a measurement can be accurately understood and replicated.
Magnetic Fields
Magnetic fields are fascinating invisible forces that have many applications and impacts in the real world. These fields are produced by moving electric charges and certain materials known as magnets. A key point to understand about magnetic fields is their strength and interaction with materials. This is where the concept of magnetic permeability comes in. Magnetic permeability is the property of a material that helps it to conduct magnetism. It measures the degree to which a material can become magnetized in an external magnetic field.
  • Highly permeable materials, like iron, enhance the magnetic field dramatically when placed in it.
  • This concept is crucial in designing magnetic circuits and electronic devices.
  • Understanding magnetic fields and permeability helps in the development of transformers, inductors, and motors.
This understanding of magnetic fields is applied in various technologies, leading to advancements in electronics and communication.
Physical Quantities
Physical quantities are measurable aspects of objects and phenomena in the physical world that can be expressed using numbers and units. They encompass everything from length, mass, and time to more complex concepts like force, energy, and magnetic permeability. When it comes to measuring magnetic permeability, we see how physical quantities quantify the ease with which a material allows a magnetic field to pass through it.
  • Physical quantities allow us to apply mathematics to the real world, predicting how systems behave under certain conditions.
  • They provide a bridge between theoretical concepts and practical applications.
  • Accurate measurement of physical quantities is at the heart of experimental science and engineering.
By studying physical quantities, scientists can derive meaningful insights and develop new technologies. In this context, understanding magnetic permeability as a physical quantity aids in material science and various engineering fields.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If Planck's constant ( \(h\) ) and speed of light in vacuum (c) are taken as two fundamental quantities, which one of the following can, in addition, be taken to express length, mass and time in terms of the three chosen fundamental quantities? \(\quad\) [NCERT Exemplar] (a) Mass of electron \(\left(m_{e}\right)\) (b) Universal gravitational constant \((G)\) (c) Charge of clectron (e) (d) Mass of proton \(\left(m_{p}\right)\)

The velocity \(v\) of water waves may depend on their wavelength \((\lambda)\), the density of water \((\rho)\) and the acceleration due to gravity \((\mathrm{g})\). The method of dimensions gives the relation between these quantities as (a) \(v^{2} \propto \lambda^{-1} \rho^{-1}\) (b) \(v^{2} \propto g \lambda\) (c) \(v^{2} \propto g \lambda \rho\) (d) \(g^{-1} \propto \lambda\)

Assertion Pressure has the dimensions of energy density. Reason Energy density \(=\frac{\text { energy }}{\text { volume }}=\frac{\left[M L^{2} T^{-2}\right]}{\left[L^{3}\right]}\) \(\left[\mathrm{ML}^{-1} \mathbf{T}^{-2}\right]=\) pressure

The number of particles given by \(n=D \frac{n_{2}-n_{1}}{x_{2}-x_{1}}\) are crossing a unit area perpendicular to \(x\)-axis in unit time, where \(n_{1}\) and \(n_{2}\) are the number of particles per unit volume for the values \(x_{1}\) and \(x_{2}\) of \(x\) respectively. Then the dimensional formula of diffusion constant \(D\) is (a) \(\left[\mathrm{M}^{0} \mathrm{LT}^{0}\right]\) (b) \(\left[\mathrm{M}^{0} \mathfrak{2}^{2} \mathrm{~T}^{-4}\right]\) (c) \(\left[\mathrm{M}^{0} \mathrm{LT}^{-3}\right]\) (d) \(\left[\mathrm{M}^{0}{ }^{2} \mathrm{~T}^{-1}\right]\)

The dimensions of distance travelled in \(n\)th second are (a) \(\left[\mathrm{M}^{0} \mathrm{LT}\right]\) (b) \(\left[\mathrm{M}^{\mathrm{O}} \mathrm{L}^{0} \mathrm{~T}^{0}\right]\) (c) \(\left[\mathrm{M}^{0} \mathrm{LT}^{-1}\right]\) (d) \(\left[\mathrm{M}^{0} \mathrm{LT}^{0}\right]\)
See all solutions

Recommended explanations on Physics Textbooks

Dynamics

Read Explanation

Kinematics Physics

Read Explanation

Fields in Physics

Read Explanation

Solid State Physics

Read Explanation

Nuclear Physics

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.