/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Suppose $$V(x)=\left\\{\begin{ar... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose $$V(x)=\left\\{\begin{array}{ll}m g x, & x>0, \\\\\infty, & x \leq 0.\end{array}\right.$$ (a) Solve the (time-independent) Schrödinger equation for this potential. Hint: First convert it to dimensionless form: \(-y^{\prime \prime}(z)+z y(z)=\epsilon y(z)\) by letting \(z \equiv a x\) and \(y(z) \equiv(1 / \sqrt{a}) \psi(x)\) (the \(\sqrt{a}\) is just so \(y(z)\) is normalized with respect to \(z\) when \(\psi(x)\) is normalized with respect to \(x\) ) What are the constants \(a\) and \(\varepsilon\) ? Actually, we might as well set \(a \rightarrow 1-\) this amounts to a convenient choice for the unit of length. Find the general solution to this equation (in Mathematica DSolve will do the job). The result is (of course) a linear combination of two (probably unfamiliar) functions. Plot each of them, for \((-15

Short Answer

Expert verified
The solution involves solving an Airy equation for eigenvalues, discarding non-normalizable functions, and plotting quantum vs. classical densities. Energy levels were found numerically, and quantum-classical resemblance emerges.

Step by step solution

01

Convert to Dimensionless Form

To convert the Schrödinger equation to dimensionless form, we first relate variables using the given transformations: let \( z = a x \) and \( y(z) = (1/\sqrt{a}) \psi(x) \). By substituting these into the potential, we focus on solving the equation \(-y''(z) + z y(z) = \epsilon y(z)\). Our goal is to determine the constants \( a \) and \( \epsilon \).
02

Determine Constants with Potential

Since \( V(x) = mgx \) for \( x > 0 \), and converting \( V(x) \) using the dimensionless transformation, we align \( V(x) \) with the term \( z \epsilon y(z) \). This suggests \( a = (mg/\hbar^2)^{1/3} \) to normalize the unit of length. Thus, \( \epsilon \) becomes a scaling factor for energy.
03

Choose Unit of Length and Solve the Equation

By letting \( a \rightarrow 1 \), we simplify the subsequent calculations and unify the system into units where this choice is effective. Solving the resulting differential equation \(-y''(z) + z y(z) = \epsilon y(z)\) using Mathematica's DSolve, we obtain a linear combination of Airy functions: \( y(z) = c_1 \text{Ai}(z - \epsilon) + c_2 \text{Bi}(z - \epsilon) \).
04

Plot and Determine Acceptable Solutions

Plot the functions \( \text{Ai}(z) \) and \( \text{Bi}(z) \) over \((-15<z<5)\). Observing the behavior of these plots, discard non-normalizable solutions - \( \text{Bi}(z) \) diverges as \( z \to \infty \), thus not acceptable for physical solutions.
05

Boundary Condition and Energy Levels

Impose the condition \( \psi(0) = 0 \), which translates in terms of Airy functions to \( \text{Ai}(-\epsilon) = 0 \). Use a root-finding tool like Mathematica's FindRoot to calculate energy levels where this condition holds, providing \( \epsilon_1 \) and \( \epsilon_{10} \).
06

Normalize and Plot Eigenfunctions

Calculate normalization constants for \( \psi_1(x) \) and \( \psi_{10}(x) \), ensuring their integrals over all space equal 1. Plot the wavefunctions for \( 0 \leq z < 16 \) observing their shapes and nodes. Verify orthogonality by evaluating the inner product of \( \psi_1(x) \) and \( \psi_{10}(x) \).
07

Calculate Uncertainties

Compute uncertainties \( \sigma_x \) and \( \sigma_p \) for states \( \psi_1(x) \) and \( \psi_{10}(x) \) using definitions \( \sigma_x^2 = \langle x^2 \rangle - \langle x \rangle^2 \) and \( \sigma_p^2 = \langle p^2 \rangle - \langle p \rangle^2 \). Check these satisfy \( \sigma_x \sigma_p \geq \hbar/2 \).
08

Compare Quantum and Classical Probability Densities

Plot \( \rho_Q(x) = |\psi(x)|^2 \) and the classical analog \( \rho_C(x) = \frac{1}{2\sqrt{\epsilon(\epsilon-x)}} \) for \( \psi_{10}(x) \). Overlay these plots and comment on similarities indicating emerging classical behavior, such as localizing around the classical path.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Schrödinger Equation
The Schrödinger Equation is a fundamental equation in quantum mechanics. It describes how the quantum state of a physical system changes over time. In this particular exercise, we focus on the time-independent Schrödinger Equation, which is used to find the allowed energy states of a quantum harmonic oscillator.
To solve this equation, we need to convert it into a more manageable, dimensionless form. By doing this, the equation becomes simpler and the solutions can be expressed in terms of known mathematical functions. We let \( z = ax \) and \( y(z) = (1/\sqrt{a}) \psi(x) \). This changes the Schrödinger equation to a simpler form: \(-y''(z) + z y(z) = \epsilon y(z)\).
In this equation, the term \(z\) represents the change in potential with respect to position, which plays a key role in finding the energy states of the system. Thanks to these transformations, we can solve the equation much more efficiently, typically using computational tools like Mathematica.
Wavefunctions
Wavefunctions, represented as \( \psi(x) \), are mathematical descriptions of the quantum state of a particle. These functions hold the key information about the system's state, including its probability distribution.
For a quantum harmonic oscillator, solving the time-independent Schrödinger Equation gives us the wavefunctions. In the exercise, the general solution to the Schrödinger Equation was a linear combination of Airy functions: \( y(z) = c_1 \text{Ai}(z - \epsilon) + c_2 \text{Bi}(z - \epsilon) \).
When plotted, these functions behave differently: \( \text{Ai}(z) \) tends to zero at infinity, making it a viable candidate for physical solutions. However, \( \text{Bi}(z) \) diverges, meaning it is not normalizable and thus discarded.
Wavefunctions also maintain a condition \( \psi(0) = 0 \), representing the boundary condition for these quantum states. This requirement helps determine only the acceptable solutions that correspond to real physical states.
Normalization
Normalization is a crucial concept in quantum mechanics, ensuring that the total probability of finding a particle within all space is 1. That is, the integral of the square of the wavefunction, \( \psi(x) \), over all space must equal 1.
In practical terms, this means calculating a normalization constant that modifies the wavefunction so that its probability distribution is correctly normalized. For the harmonic oscillator, this involves integrating \(|\psi(x)|^2\) over the desired range and ensuring the result is 1.
This process guarantees that probabilities derived from \(\psi(x)\) are meaningful and that they accurately reflect the likelihood of detecting the particle in given locations. In our step-by-step solution, we calculated the normalization factors for \( \psi_1(x) \) and \( \psi_{10}(x) \) after finding their energy levels. This confirms that these eigenfunctions are valid representations of the system's quantum states.
Uncertainty Principle
The Uncertainty Principle, formulated by Heisenberg, is a fundamental concept in quantum mechanics. It states that certain pairs of physical properties, like position (\(x\)) and momentum (\(p\)), cannot be simultaneously measured with arbitrary precision. Mathematically, this is expressed as \( \sigma_x \sigma_p \geq \hbar/2 \).
For the quantum harmonic oscillator, this principle is checked by calculating the uncertainties of position and momentum for different states. These uncertainties are derived from the variances \( \sigma_x^2 = \langle x^2 \rangle - \langle x \rangle^2 \) and \( \sigma_p^2 = \langle p^2 \rangle - \langle p \rangle^2 \).
In the exercise, we calculated \( \sigma_x \) and \( \sigma_p \) for states \( \psi_1(x) \) and \( \psi_{10}(x) \) to ensure the uncertainty principle holds. This verification underscores the inherent limitations of measuring quantum systems more precisely and serves as a cornerstone theory in quantum mechanics, emphasizing the probabilistic nature of the microscopic world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose $$V(x)=\left\\{\begin{array}{ll} m g x, & x>0 \\ \infty, & x \leq 0 \end{array}\right.$$ (a) Solve the (time-independent) Schrödinger equation for this potential. Hint: First convert it to dimensionless form: $$-y^{\prime \prime}(z)+z y(z)=\epsilon y(z)$$ by letting \(z \equiv a x\) and \(y(z) \equiv(1 / \sqrt{a}) \psi(x)\) (the \(\sqrt{a}\) is just so \(y(z)\) is normalized with respect to \(z\) when \(\psi(x)\) is normalized with respect to \(x\) ) What are the constants \(a\) and \(\varepsilon\) ? Actually, we might as well set \(a \rightarrow 1-\) this amounts to a convenient choice for the unit of length. Find the general solution to this equation (in Mathematica DSolve will do the job). The result is (of course) a linear combination of two (probably unfamiliar) functions. Plot each of them, for \((-15

Solve the time-independent Schrödinger equation for a centered infinite square well with a delta-function barrier in the middle: $$V(x)=\left\\{\begin{array}{ll}\alpha \delta(x), & -a

This problem is designed to guide you through a "proof" of Plancherel's theorem, by starting with the theory of ordinary Fourier series on a finite interval, and allowing that interval to expand to infinity. (a) Dirichlet's theorem says that "any" function \(f(x)\) on the interval \([-a,+a]\) can be expanded as a Fourier series: $$f(x)=\sum_{n=0}^{\infty}\left[a_{n} \sin \left(\frac{n \pi x}{a}\right)+b_{n} \cos \left(\frac{n \pi x}{a}\right)\right].$$ Show that this can be written equivalently as $$f(x)=\sum_{n=-\infty}^{\infty} c_{n} e^{i n \pi x / a}.$$ What is \(c_{n},\) in terms of \(a_{n}\) and \(b_{n} ?\) (b) Show (by appropriate modification of Fourier's trick) that $$c_{n}=\frac{1}{2 a} \int_{-a}^{+a} f(x) e^{-i n \pi x / a} d x.$$ (c) Eliminate \(n\) and \(c_{n}\) in favor of the new variables \(k=(n \pi / a)\) and \(F(k)=\sqrt{2 / \pi} a c_{n} .\) Show that \((\mathrm{a})\) and \((\mathrm{b})\) now become $$f(x)=\frac{1}{\sqrt{2 \pi}} \sum_{n=-\infty}^{\infty} F(k) e^{i k x} \Delta k ; \quad F(k)=\frac{1}{\sqrt{2 \pi}} \int_{-a}^{+a} f(x) e^{-i k x} d x, $$ where \(\Delta k\) is the increment in \(k\) from one \(n\) to the next. (d) Take the limit \(a \rightarrow \infty\) to obtain Plancherel's theorem. Comment: In view of their quite different origins, it is surprising (and delightful) that the two formulas-one for \(F(k)\) in terms of \(f(x),\) the other for \(f(x)\) in terms of \(F(k)-\) have such a similar structure in the limit \(a \rightarrow \infty.\)

Evaluate the following integrals: (a) \(\int_{-3}^{+1}\left(x^{3}-3 x^{2}+2 x-1\right) \delta(x+2) d x.\) (b) \(\int_{0}^{\infty}[\cos (3 x)+2] \delta(x-\pi) d x.\) (c) \(\int_{-1}^{+1} \exp (|x|+3) \delta(x-2) d x.\)

The gaussian wave packet. A free particle has the initial wave function \(\Psi(x, 0)=A e^{-a x^{2}}\) where \(A\) and \(a\) are (real and positive) constants. (a) Normalize \(\Psi(x, 0)\) (b) Find \(\Psi(x, t)\). Hint: Integrals of the form $$\int_{-\infty}^{+\infty} e^{-\left(a x^{2}+b x\right)} d x$$ can be handled by "completing the square": Let \(y \equiv \sqrt{a}[x+(b / 2 a)]\) and note that \(\left(a x^{2}+b x\right)=y^{2}-\left(b^{2} / 4 a\right) .\) Answer (c) Find \(|\Psi(x, t)|^{2}\). Express your answer in terms of the quantity \(w \equiv \sqrt{a /\left[1+(2 \hbar a t / m)^{2}\right]}\) Sketch \(|\Psi|^{2}(\text { as a function of } x)\) at \(t=0,\) and again for some very large \(t\) Qualitatively, what happens to \(|\Psi|^{2},\) as time goes on? (d) \(\quad\) Find \(\langle x\rangle,\langle p\rangle,\left\langle x^{2}\right\rangle,\left\langle p^{2}\right\rangle, \sigma_{x},\) and \(\sigma_{p} .\) Partial answer: \(\left\langle p^{2}\right\rangle=a \hbar^{2},\) but it may take some algebra to reduce it to this simple form. (e) Does the uncertainty principle hold? At what time \(t\) does the system come closest to the uncertainty limit?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.