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Prove the following three theorem;

a) For normalizable solutions the separation constant E must be real as E0+iand show that if equation 1.20 is to hold for all t, must be zero.

b) The time - independent wave function localid="1658117146660" (x) can always be taken to be real, This doesn鈥檛 mean that every solution to the time-independent Schrodinger equation is real; what it says is that if you鈥檝e got one that is not, it can always be expressed as a linear combination of solutions that are . So, you might as well stick to 鈥檚 that are real

c) If is an even function then (x)can always be taken to be either even or odd

Short Answer

Expert verified

(a) The wave-function normalized we make =0, and in general,Esmust be real for a normalized wave-function.

(b),*and any linear combination of them satisfy eq. (2.5).

(c) An even wave-function, an odd wave-function, and any linear combination of them satisfy eq.(2.5) if the potential function is even.

Step by step solution

01

Step 1: Define the Schrodinger equation

Schr枚dinger's wave equation, sometimes known as the Schr枚dinger equation, is a partial differential equation that uses the wave function to explain how quantum mechanical systems behave. The trajectory, position, and energy of these systems can be determined using the Schr枚dinger equation.

02

Determine the equation is normalized

(a)

ConsiderE=E0+i, whereE,. Now, we calculate the probability density of the time-dependent wave function .

x,t2=*=*eE0-颈螕t/蠄别-E0-颈螕t/=2e2螕迟/

To check the normalizability of this wave-function, we integrate over all space.

-x,t2=-2e2t/dx=e2t/-2dx=e2t/

So, it is not normalized (because the energy is not real), so to make it normalized we make =0, and in general,E must be real for a normalized wave-function.

03

Determine the real solutions

(b)

Eq.(2.5) is

22md2dx2+V=E

Now, if satisfy this equation, then its conjugate *also satisfy eq.(2.5), where and *are complex.

22md2dx2+V*=E*

So, any linear combination of these two function must satisfy eq.(2.5) too (i.g.,+*and i=*), in general

=a1+a2x

Where and xare wave-functions, and a1and a2are complex constants.

-22md2dx2+V=-22md2a1+a2xdx2+Va1+a2x=Ea1+a2x

-22ma1d2dx2+a2d2xdx2+a1V+a2Vx=a1E+2Ex-22ma1d2dx2+a2d2xdx2+a1V+a2Vx=a1E+2Exa1-22md2dx2+V+a2-22md2xdx2+Vx=a1E+a2Ex-22md2dx2+V=E

So from any complex solution, we can always construct two real solutions.

04

Determine the general solution

(c)

For an odd time-independent wave-function -x=-x, so

-22md2xdx2-痴蠄x=-贰蠄x

Therefore,

-22md2xdx2+痴蠄x=-贰蠄x

For an even time-independent wave-function-x=x, so

-22md2xdx2+痴蠄-x=贰蠄-x-22md2xdx2+痴蠄x=-贰蠄x

As we have see, both (the even and odd wave-function) satisfy eq.(2.5), so any

linear combination must satisfy this equation too, whereevenx=12x+-x, and oddx=12x--x.

The general solution can then be built from a linear combination of even and odd functions.

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Most popular questions from this chapter

Find the allowed energies of the half harmonic oscillator

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