/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5.21P Is Ampere's law consistent with ... [FREE SOLUTION] | 91影视

91影视

Is Ampere's law consistent with the general rule (Eq. 1.46) that divergence-of-curl is always zero? Show that Ampere's law cannot be valid, in general, outside magnetostatics. Is there any such "defect" in the other three Maxwell equations?

Short Answer

Expert verified

The divergence of curl is not always equal to zero and it is proved that the ampere鈥檚 law is not valid outside the magnetostatics. The defect in this equation is not consistence in general rule.

Step by step solution

01

Write the given data from the question.

The divergence of curl is always zero.

(.v)=0

02

Determine the maxwell’s equation of space in different form

Write all the Maxwell equations:

E=0B=0E=-BtB=0J

Here,role="math" localid="1658226949122" E is the electric field, Bis the magnetic field, is the charge density, 0permittivity of space, 0is the permeability of the space and Jis the current density.

03

Show that the divergence of curl is always zero and ampere law is not valid outside the magnetostatics.

The expression for the continuity equation is given by,

J+ddt=0J=ddt

The expression for the ampere鈥檚 law is given by,

B=0J

Take the divergence of both the sides of the above equation.

(B)=(0J)(B)=0(J)

Substituteddtfor Jinto above equation.

From the above it is proved that the value of curl is not equal to zero unless the charge density is constant quantity.

Therefore, it is proved that the ampere鈥檚 law is not valid for outside the magnetostatics.

Consider the Maxwell鈥檚 equations as,

E=Bt

Take the divergence of both the sides of the above equation.

Substitute for into above equation.

(E)=(Bt)(E)=ddtB(E)=ddt(B)

Substitute0forBinto above equation.

(E)=ddt(0)(E)=0

Hence from the above, consistence of curl is zero.

The two equations are E=oand B=0are the divergence equation and can鈥檛 be vanished by any form.

Therefore, defect in this equation is not consistence with the general rule of Eq. 1.46.

Hence the divergence of curl is not always equal to zero and it is proved that the ampere鈥檚 law is not valid outside the magnetostatics. The defect in this equation is not consistence in general rule.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A thin glass rod of radius Rand length Lcarries a uniform surfacecharge .It is set spinning about its axis, at an angular velocity .Find the magnetic field at a distances sR from the axis, in the xyplane (Fig. 5.66). [Hint:treat it as a stack of magnetic dipoles.]

Another way to fill in the "missing link" in Fig. 5.48 is to look for a magnetostatic analog to Eq. 2.21. The obvious candidate would be

A(r)=0r(Bdl)

(a) Test this formula for the simplest possible case-uniform B (use the origin as your reference point). Is the result consistent with Prob. 5.25? You could cure this problem by throwing in a factor of localid="1657688349235" 12, but the flaw in this equation runs deeper.

(b) Show that (Bdl)is not independent of path, by calculating (Bdl)around the rectangular loop shown in Fig. 5.63.

Figure 5.63

As far as lknow,28the best one can do along these lines is the pair of equations

(i) localid="1657688931461" v(r)=-r01E(r)诲位

(ii) A(r)=-r01位叠(位谤)诲位

[Equation (i) amounts to selecting a radial path for the integral in Eq. 2.21; equation (ii) constitutes a more "symmetrical" solution to Prob. 5.31.]

(c) Use (ii) to find the vector potential for uniform B.

(d) Use (ii) to find the vector potential of an infinite straight wire carrying a steady current. Does (ii) automatically satisfy A=0[Answer:(ol/2蟺蝉)(zs^-sz^) ].

Question: Use Eq. 5.41 to obtain the magnetic field on the axis of the rotating disk in Prob. 5.37(a). Show that the dipole field (Eq. 5.88), with the dipole moment you found in Prob. 5.37, is a good approximation if z>> R.

Show that the magnetic field of a dipole can be written in coordinate-free form:

Bdip(r)=041r3[3(mr^)r^-m]

(a) Complete the proof of Theorem 2, Sect. 1.6.2. That is, show that any divergenceless vector field F can be written as the curl of a vector potential . What you have to do is find Ax,Ayand Azsuch that (i) Az/y-Ay/z=Fx; (ii) Ax/z-Az/x=Fy; and (iii) Ay/x-Ax/y=Fz. Here's one way to do it: Pick Ax=0, and solve (ii) and (iii) for Ayand Az. Note that the "constants of integration" are themselves functions of y and z -they're constant only with respect to x. Now plug these expressions into (i), and use the fact that F=0to obtain

Ay=0xFz(x',y,z)dx';Az=0yFx(0,y',z)dy'-0yFy(x',y,z)dx'

(b) By direct differentiation, check that the you obtained in part (a) satisfies A=F. Is divergenceless? [This was a very asymmetrical construction, and it would be surprising if it were-although we know that there exists a vector whose curl is F and whose divergence is zero.]

(c) As an example, let F=yx^+zy^+xz^. Calculate , and confirm that A=F. (For further discussion, see Prob. 5.53.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.