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Show that the magnetic field of a dipole can be written in coordinate-free form:

Bdip(r)=μ04π1r3[3(m⋅r^)r^-m]

Short Answer

Expert verified

The magnetic field of a dipoleμ04Ï€°ù3[(3m⃗⋅r^)r^-m⃗] has been proved.

Step by step solution

01

Significance of the magnetism

Magnetism is a type of physical phenomenon produced by a motion of electric charges. Magnetism significantly results in repulsive or attractive force amongst the objects.

02

Determination of the magnetic field of a dipole

The equation of the dipole magnetic field is expressed as:

B=μ0m4Ï€°ù32cosθr^+sinθθ^=μ0m4Ï€°ù3z^ ...... (i)

Here, μ0is the permeability, m is the magnetic dipole moment ,r is the distance between the dipole charges, z^is the position vector in the z direction, and θis the angle between the dipoles.

If the dipole orients towards the z axis, then the equation of the magnetic dipole moment can be expressed as:

m→=mz^

Here, m→is the magnetic dipole moment vector and z^is the position vector in the z direction.

Substitute ³¦´Ç²õθr^-²õ¾±²Ôθθ^forz^in the above equation.

m→=m³¦´Ç²õθr^-²õ¾±²Ôθθ^=m³¦´Ç²õθr^-m²õ¾±²Ôθθ^=m→.r^r^-m³¦´Ç²õθr^-m→=2m→.r^r^+m→.r^r^-m→

Hence, further as:

m→=2m→.r^r^+m→.r^r^-m→=3m→.r^r^-m→

Substitute the above value in equation (i).

localid="1657530579098" B=μ04Ï€°ù3[(3m⃗⋅r^)r^-m⃗]

Thus, the magnetic field of a dipolelocalid="1657528216508" μ04Ï€°ù3[(3m⃗⋅r^)r^-m⃗]has been proved.

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Most popular questions from this chapter

thick slab extending from z=-ato z=+a(and infinite in the x andy directions) carries a uniform volume current J=Jx^(Fig. 5.41). Find the magnetic field, as a function of z, both inside and outside the slab.

A uniformly charged solid sphere of radius Rcarries a total charge Q, and is set spinning with angular velocitywabout the zaxis.

(a) What is the magnetic dipole moment of the sphere?

(b) Find the average magnetic field within the sphere (see Prob. 5.59).

(c) Find the approximate vector potential at a point (r,B)where r>R.

(d) Find the exact potential at a point (r,B)outside the sphere, and check that it is consistent with (c). [Hint: refer to Ex. 5.11.]

(e) Find the magnetic field at a point (r, B) inside the sphere (Prob. 5.30), and check that it is consistent with (b).

A particle of charge qenters a region of uniform magnetic field B→ (pointing intothe page). The field deflects the particle a distanced above the original line of flight, as shown in Fig. 5.8. Is the charge positive or negative? In terms of a, d, Band q,find the momentum of the particle.

A thin glass rod of radius Rand length Lcarries a uniform surfacecharge δ .It is set spinning about its axis, at an angular velocity Ӭ.Find the magnetic field at a distances s≫R from the axis, in the xyplane (Fig. 5.66). [Hint:treat it as a stack of magnetic dipoles.]

(a) Complete the proof of Theorem 2, Sect. 1.6.2. That is, show that any divergenceless vector field F can be written as the curl of a vector potential . What you have to do is find Ax,Ayand Azsuch that (i) ∂Az/∂y-∂Ay/∂z=Fx; (ii) ∂Ax/∂z-∂Az/∂x=Fy; and (iii) ∂Ay/∂x-∂Ax/∂y=Fz. Here's one way to do it: Pick Ax=0, and solve (ii) and (iii) for Ayand Az. Note that the "constants of integration" are themselves functions of y and z -they're constant only with respect to x. Now plug these expressions into (i), and use the fact that ∇⋅F=0to obtain

Ay=∫0xFz(x',y,z)dx';Az=∫0yFx(0,y',z)dy'-∫0yFy(x',y,z)dx'

(b) By direct differentiation, check that the you obtained in part (a) satisfies ∇×A=F. Is divergenceless? [This was a very asymmetrical construction, and it would be surprising if it were-although we know that there exists a vector whose curl is F and whose divergence is zero.]

(c) As an example, let F=yx^+zy^+xz^. Calculate , and confirm that ∇×A=F. (For further discussion, see Prob. 5.53.)

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