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Suppose that the magnetic field in some region has the form

B→=kzxÁåœ

(where kis a constant). Find the force on a square loop (side a),lying in the yz

plane and centered at the origin, if it carries a current I,flowing counterclockwise,

when you look down the xaxis.

Short Answer

Expert verified

The force on a square loop of side a,lying in the yzplane and centered at the origin, carrying a current I,flowing counterclockwise in the presence of a magnetic fieldB→=kzxÁåœ is Ia2kzÁåœ.

Step by step solution

01

Given data

There is a magnetic field of the formB→=kzxÁåœ .

There is a square loop of side alying in the yzplane, centered at the origin and carries a current I,flowing counterclockwise.

02

Force on a current carrying wire in a magnetic field

The force on a wire carrying current I, length Iin a magnetic fieldBis

F→=||→×B→......(1)

03

Force on the current carrying loop

The force on y=a/2and y=-a/2wires are exactly equal and opposite and so they cancel out.

From equation (1), force on the z=a/2 wire

F→1=IaB\z-a/2zÁåœ=Iaka2zÁåœ=Ia2k2zÁåœ

From equation (1), force on the z=-a/2 wire

F→2=IaB\z-a/2-zÁåœ=Iak-a2-zÁåœ=Ia2k2zÁåœ

Thus, the net force on the wire is Ia2kzÁåœ .

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Most popular questions from this chapter

In 1897, J. J. Thomson "discovered" the electron by measuring the

charge-to-mass ratio of "cathode rays" (actually, streams of electrons, with charge qand mass m)as follows:

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