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In calculating the current enclosed by an Amperian loop, one must,in general, evaluate an integral of the form

Ienc=∫sJ⋅da

The trouble is, there are infinitely many surfaces that share the same boundary line. Which one are we supposed to use?

Short Answer

Expert verified

As a result, any particular surface can be considered for an endless number of surfaces with the same boundary line because the integral is independent of the surface.

Step by step solution

01

Define function

Here, The sum of the enclosed currents times the permeability of free space is equal to the closed line integral of the magnetic field multiplied by the length of the curve, according to Ampere's law.

Write the expression for the ampere’s law.

∮B⋅dl=μ0∑Ienc …… (1)

Here,μ0 is the permeability for free space,B is the magnetic field, dlis the length of curve, Iencis the enclosed current.

Write the expression for value of current enclosed in terms of current density.

Ienc=∫sJ⋅da …… (2)

Here, Jis the current density andIenc is the enclosed current.

02

Determine solution

The integral is surface independent, according to the divergence less field’s theorem. Any given boundary line's integral∫J⋅da value will be the same. For an enclosed surface, the integral value will be 0. In addition, the current density should have a lower divergence than the following criterion.

∇⋅J=0 …… (3)

As a result, any particular surface can be considered for an endless number of surfaces with the same boundary line because the integral is independent of the surface.

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Most popular questions from this chapter

Is Ampere's law consistent with the general rule (Eq. 1.46) that divergence-of-curl is always zero? Show that Ampere's law cannot be valid, in general, outside magnetostatics. Is there any such "defect" in the other three Maxwell equations?

Two long coaxial solenoids each carry current I , but in opposite directions, as shown in Fig. 5.42. The inner solenoid (radius a) has turns per unit length, and the outer one (radius b) has .n2Find B in each of the three regions: (i) inside the inner solenoid, (ii) between them, and (iii) outside both.

A uniformly charged solid sphere of radius Rcarries a total charge Q, and is set spinning with angular velocitywabout the zaxis.

(a) What is the magnetic dipole moment of the sphere?

(b) Find the average magnetic field within the sphere (see Prob. 5.59).

(c) Find the approximate vector potential at a point (r,B)where r>R.

(d) Find the exact potential at a point (r,B)outside the sphere, and check that it is consistent with (c). [Hint: refer to Ex. 5.11.]

(e) Find the magnetic field at a point (r, B) inside the sphere (Prob. 5.30), and check that it is consistent with (b).

If B is uniform,show that A(r)=-12(r×B)works. That is, check that ∇.A=0and∇×A=B. Is this result unique, or are there other functions with the same divergence and curl?

The magnetic field on the axis of a circular current loop (Eq. 5.41) is far from uniform (it falls off sharply with increasing z). You can produce a more nearly uniform field by using two such loops a distanced apart (Fig. 5.59).

(a) Find the field (B) as a function of z, and show that ∂B∂zis zero at the point midway between them (z=0)

(b) If you pick d just right, the second derivative ofBwill also vanish at the midpoint. This arrangement is known as a Helmholtz coil; it's a convenient way of producing relatively uniform fields in the laboratory. Determine dsuch that

∂2B/∂z2=0at the midpoint, and find the resulting magnetic field at the center.

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