91Ó°ÊÓ

The number of turns in the primary coils are,$N_1$.

The number of turns in the secondary coils are,$N_2$.

The current passing through the primary coil is,I .

When the magnitude of the current flowing in the coil varies, a magnetic flux is generated and a certain amount of emf is also induced in the coil.

If the number of turns in the coil are increased then the magnetic flux produced in the coil also increases.

When the current passes through a single loop of primary coil, the magnetic field is generated and the change in current value creates the magnetic flux$\mathrm{Φ}$.

Then, the formula for the magnetic flux on the primary coil is given by,

localid="1658291056948" ${\mathrm{Φ}}_1={\mathrm{N}}_1\mathrm{Φ}$

And, the formula for the magnetic flux on the secondary coil is given by,

localid="1658291081661" ${\mathrm{Φ}}_2={\mathrm{N}}_2\mathrm{Φ}$

The formula for the emf induced in the primary coil is given by,

$$\begin{gathered} {\mathrm{Î\mu }}_1=-\frac{d{\mathrm{Φ}}_1}{dt} \\ {\mathrm{Î\mu }}_1=-\frac{d\left(N_1\mathrm{Φ}\right)}{dt} \\ {\mathrm{Î\mu }}_1=-N_1\frac{d\mathrm{Φ}}{dt}........\left(1\right) \end{gathered}$$

The formula for the emf induced in the secondary coil is given by,

$$\begin{gathered} {\mathrm{Î\mu }}_2=-\frac{d{\mathrm{Φ}}_2}{dt} \\ {\mathrm{Î\mu }}_2=-\frac{d\left(N_2\mathrm{Φ}\right)}{dt} \\ {\mathrm{Î\mu }}_2=-N_2\frac{d\mathrm{Φ}}{dt}.......\left(2\right) \end{gathered}$$

By dividing equation (2) by equation (1),

$$\begin{gathered} \frac{{\mathrm{Î\mu }}_2}{{\mathrm{Î\mu }}_1}=\frac{-N_2\frac{d\mathrm{Φ}}{dt}}{-N_1\frac{d\mathrm{Φ}}{dt}} \\ \frac{{\mathrm{Î\mu }}_2}{{\mathrm{Î\mu }}_1}=\frac{N_2}{N_1} \end{gathered}$$

Hence proved.