/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 The position vector for an clect... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The position vector for an clectron is \(\vec{r}=(5.0 \mathrm{~m}) \hat{\mathrm{i}}-\) \((3.0 \mathrm{~m}) \hat{\mathrm{j}}+(2.0 \mathrm{~m}) \hat{\mathrm{k}},(\mathrm{a})\) Find the magnitude of \(\vec{r} .\) (b) Sketch the vector on a right-handed coordinate system.

Short Answer

Expert verified
(a) Magnitude is \(\sqrt{38}\) meters. (b) Sketch involves plotting the vector in 3D starting from the origin.

Step by step solution

01

Understanding the Magnitude Formula

To find the magnitude of a vector \(\vec{r} = a \hat{i} + b \hat{j} + c \hat{k}\), we use the formula: \[||\vec{r}|| = \sqrt{a^2 + b^2 + c^2}\] where \(a, b,\) and \(c\) are the components of the vector along the \(\hat{i}, \hat{j},\) and \(\hat{k}\) directions, respectively.
02

Substituting the Components

Substitute the components of the position vector \(\vec{r} = (5.0 \ \mathrm{m})\hat{\mathrm{i}} - (3.0 \ \mathrm{m})\hat{\mathrm{j}} + (2.0 \ \mathrm{m})\hat{\mathrm{k}}\) into the formula. Here, \(a = 5.0\), \(b = -3.0\), and \(c = 2.0\).
03

Calculating the Magnitude

Calculate the magnitude using the formula: \[||\vec{r}|| = \sqrt{(5.0)^2 + (-3.0)^2 + (2.0)^2} = \sqrt{25 + 9 + 4} = \sqrt{38}\]Thus, the magnitude of \(\vec{r}\) is \(\sqrt{38}\) meters.
04

Sketching the Vector

To sketch the vector, plot the initial point of the vector at the origin \((0,0,0)\) of a 3D coordinate system. From there, move 5 units along the \(\hat{i}\) direction, -3 units along the \(\hat{j}\) direction (negative indicates moving opposite to the positive \(\hat{j}\) axis), and 2 units along the \(\hat{k}\) direction. This represents the vector \(\vec{r}\) in the 3D space.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Vector
A position vector beautifully describes the position or the location of a point in a space with respect to a chosen origin. Consider it as an arrow pointing from the origin to a specific point. In the given exercise, the position vector \( \vec{r} = (5.0 \mathrm{~m}) \hat{\mathrm{i}} - (3.0 \mathrm{~m}) \hat{\mathrm{j}} + (2.0 \mathrm{~m}) \hat{\mathrm{k}} \) tells us exactly where the electron is, relative to the origin in a 3D space.

These components \((a = 5.0, b = -3.0, c = 2.0)\) are its coordinates along the x, y, and z axes respectively.
  • \(5.0 \mathrm{~m} \) along \(\hat{\mathrm{i}}\) or the x-axis
  • \(-3.0 \mathrm{~m} \) along \(\hat{\mathrm{j}}\) or the y-axis, indicating movement in the opposite direction
  • \(2.0 \mathrm{~m} \) along \(\hat{\mathrm{k}}\) or the z-axis
By understanding these components, you can visualize precisely where the point is in 3D space.
3D Coordinate System
A 3D coordinate system is something like a stage, where vectors dance in three-dimensions. It consists of three axes: the x-axis, the y-axis, and the z-axis. Imagine a room where you stand in one corner - the place you're standing is the origin.

The axes are like invisible lines that run along the edges of the room. The x-axis goes along the floor left and right, the y-axis moves along the floor front and back, while the z-axis goes from the floor to the ceiling. This provides a basis to describe any position in this space using three numbers, often referred to as coordinates.
  • Horizontal plane is defined by the x and y axes.
  • The vertical aspect is introduced by the z-axis.
  • All positions can be traced back to the origin (0,0,0).
This handy setup helps in understanding where vectors point and how far their reach extends within the three-dimensional world.
Vector Components
When talking about vectors, we often break them down into simpler parts called components. These components reflect how much of the vector stretches in each direction: x, y, and z. In simpler terms, it's like splitting a vector into simple straight-line journeys that tell how far you must travel in each direction to get to your final destination.

The position vector \( \vec{r}\) can be expressed by its components: \(5.0 \mathrm{~m} \) in the x-direction, \(-3.0 \mathrm{~m} \) in the y-direction, and \(2.0 \mathrm{~m} \) in the z-direction, as seen in the given exercise.
  • The x-component indicates movement left or right along the x-axis.
  • The y-component measures the movement forward or backward along the y-axis.
  • The z component determines upward or downward motion along the z-axis.
Breaking down vectors this way simplifies many complex calculations and clarifies how we arrive at the overall vector magnitude using the Pythagorean theorem in three dimensions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A projectile's launch speed is five times its speed at maximum height. Find launch angle \(\theta_{0}\).

A dart is thrown horizontally with an initial speed of \(10 \mathrm{~m} / \mathrm{s}\) toward point \(P\), the bull's-eye on a dart board. It hits at point \(Q\) on the rim, vertically below \(P, 0.19 \mathrm{~s}\) later. (a) What is the distance \(P Q ?\) (b) How far away from the dart board is the dart released?

A plane, diving with constant speed at an angle of \(53.0^{\circ}\) with the vertical, releases a projectile at an altitude of \(730 \mathrm{~m}\). The projectile hits the ground \(5.00 \mathrm{~s}\) after release. (a) What is the speed of the plane? (b) How far does the projectile travel horizontally during its flight? What are the (c) horizontal and (d) vertical components of its velocity just before striking the ground?

A moderate wind accelerates a pebble over a horizontal \(x y\) plane with a constant acceleration \(\vec{a}=\left(5.00 \mathrm{~m} / \mathrm{s}^{2}\right) \hat{\mathrm{i}}+\left(7.00 \mathrm{~m} / \mathrm{s}^{2}\right) \mathrm{j}\). At time \(t=0\), the velocity is \((4.00 \mathrm{~m} / \mathrm{s})\) i. What are the (a) magnitude and (b) angle of its velocity when it has been displaced by \(12.0\) \(\mathrm{m}\) parallel to the \(x\) axis?

An electron's position is given by \(\vec{r}=3.00 t \hat{\mathrm{i}}-\) \(4.00 t^{2} \hat{\mathrm{j}}+2.00 \hat{\mathrm{k}}\), with \(t\) in seconds and \(\vec{r}\) in meters. (a) In unit-vector notation, what is the electron's velocity \(\vec{v}(t)\). At \(t=2.00 \mathrm{~s}\), what is \(\vec{v}\) (b) in unit- vector notation and as (c) a magnitude and (d) an angle relative to the positive direction of the \(x\) axis?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.