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Monochromatic light of wavelength \(441 \mathrm{nm}\) is incident on a narrow slit. On a screen \(2.00 \mathrm{~m}\) away, the distance between the second diffraction minimum and the central maximum is \(1.50 \mathrm{~cm}\). (a) Calculate the angle of diffraction \(\theta\) of the second minimum. (b) Find the width of the slit.

Short Answer

Expert verified
(a) The angle of diffraction \( \theta \) is approximately \( 0.429 \text{ degrees}. \) (b) The width of the slit is \( 0.1176 \text{ mm}. \)

Step by step solution

01

Understanding Diffraction Minima

For a single slit, diffraction minima are given by the equation \( a \sin \theta = m \lambda \), where \( a \) is the slit width, \( m \) is the order of the minimum (for the second minimum, \( m = 2 \)), and \( \lambda \) is the wavelength of light. We aim to find the angle \( \theta \) for this diffraction minimum.
02

Calculate the Angle of Diffraction \( \theta \)

Using the geometry of the diffraction pattern on the screen, the distance \( y \) from the central maximum to the second minimum is given as \( 0.015 \) m. The angle \( \theta \) can be approximated as \( \tan \theta = \frac{y}{L} \), where \( L = 2 \) m is the distance to the screen. Calculate \( \theta \) using \( \theta \approx \tan \theta \approx \frac{0.015}{2} = 0.0075 \). Hence, \( \theta \approx 0.0075 \) radians.
03

Relate \( \theta \) to Sin Function

Since \( \theta \) is small, \( \sin \theta \approx \theta \approx 0.0075 \). Thus, this approximation helps us work with the diffraction condition equation without significant error.
04

Calculate the Slit Width \( a \)

Substitute known values into the diffraction minima equation: \( a \cdot 0.0075 = 2 \times 441 \times 10^{-9} \). Solve for \( a \): \[ a = \frac{2 \times 441 \times 10^{-9}}{0.0075} = 1.176 \times 10^{-4} \text{ meters} = 0.1176 \text{ mm}. \] Thus, the width of the slit is \( 0.1176 \text{ mm} \).
05

Answer for Angle of Diffraction

Convert \( \theta \approx 0.0075 \) radians to degrees using the conversion factor \( 1 \text{ radian} = 57.2958 \text{ degrees} \). Calculate: \( \theta \approx 0.0075 \times 57.2958 \approx 0.429 \text{ degrees}. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength of Light
The term "wavelength of light" is fundamental in understanding optical phenomena such as diffraction. Wavelength, often denoted by the Greek letter lambda (\(\lambda\)), represents the distance between consecutive peaks of a wave.
In the context of light, this is the distance a light wave travels in one complete oscillation. For visible light, wavelengths range from approximately 380 nm to 750 nm. In our exercise, the light's wavelength is 441 nm, which falls within the blue region of visible light.
Understanding the wavelength is crucial because it influences how light interacts with objects, such as slits in a diffraction experiment. When light encounters a slit of size comparable to its wavelength, diffraction patterns are produced, displaying alternating light and dark bands. Each wavelength will diffract differently, forming unique patterns associated with its specific wavelength.
Diffraction Minima
Diffraction minima refer to the dark or minimal intensity areas in a diffraction pattern. These occur due to destructive interference, where light waves cancel each other.
For a single slit, diffraction minima are observed at specific angles, forming distinct patterns on a screen. The angles at which these minima occur depend on the light's wavelength and the slit width, described by the equation \( a \sin \theta = m \lambda \). Here, \(a\) is the slit width, \(\theta\) is the angle of diffraction, and \(m\) is the order of the minimum. The value of \(m\) is typically a whole number, representing different orders of minima.
In this exercise, we calculated the position of the second diffraction minimum (\(m=2\)), which helps us find important characteristics like the angle of the diffraction pattern.
Single Slit Diffraction
Single slit diffraction occurs when light passes through a narrow slit and spreads out rather than traveling in a straight line. This phenomenon can be explained using the wave nature of light, where light waves spread after passing through the slit, interfering with each other.
The single slit setup is particularly interesting because it results in a central bright fringe (maximum) accompanied by alternating dark (minimum) and bright lines. The complexity of the pattern is influenced by the slit width relative to the light's wavelength.
In our scenario, light of 441 nm wavelength produces a pattern with visible diffraction minima, and the central maximum is a key reference point for measurements. This setup allows us to calculate important properties like the slit width or the angle of diffraction, providing insights into how light behaves at this scale.
Angle of Diffraction
The angle of diffraction is a key concept in understanding and measuring diffraction patterns. It describes how far a wave, such as light, is bent as it passes through a slit or around an object.
Using a simple relation \( \tan \theta = \frac{y}{L} \), where \(y\) is the distance from the central maximum to a diffraction minimum on the screen and \(L\) is the distance from the slit to the screen, we can approximate \(\theta\) for small angles.
For our exercise, the angle was approximately \(0.0075\) radians, which is quite small. In such cases, \(\sin \theta \) can be approximated to \(\theta\), simplifying our calculations without significant error. This angle determination is crucial for accurately describing the diffraction pattern and further finding the slit width.

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