/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Assume that the limits of the vi... [FREE SOLUTION] | 91Ó°ÊÓ

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Assume that the limits of the visible spectrum are arbitrarily chosen as 430 and \(680 \mathrm{nm}\). Calculate the number of rulings per millimeter of a grating that will spread the first-order spectrum through an angle of \(20.0^{\circ}\).

Short Answer

Expert verified
Approximately 617 rulings per millimeter are needed.

Step by step solution

01

Understand the formula for diffraction grating

The grating equation relates the number of lines per unit length, the wavelength \( \lambda \), the order \( m \), and the angle \( \theta \). It is given by \( d \sin \theta = m \lambda \), where \( d \) is the distance between the rulings (grating spacing).
02

Convert the given angle to radians

The angle given is \( 20.0^{\circ} \). Since many trigonometric calculations use radians, convert this angle using the formula: \( \theta = 20.0^{\circ} \times \frac{\pi}{180^{\circ}} \approx 0.349 \) radians.
03

Solve the grating equation for \( d \)

For the first order spectrum \( m = 1 \), using the midpoint wavelength of the visible spectrum \( \lambda = \frac{430 + 680}{2} = 555 \text{ nm} = 555 \times 10^{-9} \text{ m} \), apply the equation: \( d \sin(0.349) = 1 \times 555 \times 10^{-9} \).
04

Calculate the value of \( d \)

Rearranging the equation, \( d = \frac{555 \times 10^{-9}}{\sin(0.349)} \approx 1.62 \times 10^{-6} \text{ m} \). This is the grating spacing needed.
05

Convert \( d \) from meters to millimeters

Convert \( d \) into millimeters because we need the number of rulings per millimeter: \( 1.62 \times 10^{-6} \text{ m} = 1.62 \times 10^{-3} \text{ mm} \).
06

Calculate the number of rulings per millimeter

The number of rulings per millimeter is the reciprocal of the grating spacing in millimeters: \( \frac{1}{1.62 \times 10^{-3}} \approx 617.28 \). Therefore, approximately 617 rulings per millimeter are needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grating Equation
The grating equation is a fundamental concept used to describe diffraction patterns created by a diffraction grating. A diffraction grating consists of many fine, equally spaced lines, known as rulings. These rulings cause light to be spread out into its different wavelengths, forming a spectrum.
To understand how a grating works, we can use the grating equation, defined as: \[ d \sin \theta = m \lambda \] where:
  • \(d\) is the distance between adjacent lines, or the grating spacing,
  • \(\theta\) is the angle of the diffracted light,
  • \(m\) is the order of the spectrum (an integer),
  • \(\lambda\) is the wavelength of the light.
The grating equation allows us to calculate the angle at which different wavelengths of light will be diffracted. In the context of our exercise, it helps us determine the necessary number of rulings per millimeter on a grating to achieve a desired spread of light across an angle.
Visible Spectrum
The visible spectrum refers to the range of electromagnetic wavelengths that the human eye can detect. This typically spans from about 400 to 700 nanometers (nm). In our exercise, we use a slightly arbitrary range of 430 to 680 nm to represent the visible spectrum, simplifying our calculations.
The colors we see in a rainbow, for example, are different parts of the visible spectrum. When light passes through a diffraction grating, each color bends at a slightly different angle. This is what creates a spread of colors, or a spectrum.
Understanding the visible spectrum is crucial in applications like spectroscopy, where scientists use these differences in wavelength to identify materials or measure concentrations of substances.
Rulings Per Millimeter
Rulings per millimeter is a key measurement in creating a diffraction grating. It refers to how many lines or rulings are etched into a grating within the span of one millimeter. This closely relates to the grating spacing, or \(d\) in the grating equation.
The more rulings there are per millimeter, the smaller the value of \(d\). This in turn affects how light is diffracted through the grating, causing light to spread out at different angles. In our exercise, calculating the number of rulings per millimeter was essential to achieve the desired angle of the first-order spectrum.
This property of a grating is significant in practical applications like spectroscopy, where precise control over diffraction angles can be critical for analyzing substances accurately.
Spectroscopy
Spectroscopy is a powerful analytical technique that employs the use of diffraction gratings to study how light interacts with matter. This scientific method allows for the identification and quantification of substances based on their spectrum.
In spectroscopy, light of various wavelengths is separated using devices like diffraction gratings. By measuring the specific wavelengths emitted or absorbed by a substance, researchers can deduce its composition and other properties.
Diffraction gratings are essential in creating high-resolution spectrometers, which are used across many fields such as chemistry, physics, and astronomy.
Understanding how rulings per millimeter and the grating equation contribute to forming a spectrum helps in grasping the mechanisms behind spectroscopy's analytical power.

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Most popular questions from this chapter

A double-slit system with individual slit widths of \(0.030 \mathrm{~mm}\) and a slit separation of \(0.18 \mathrm{~mm}\) is illuminated with \(500 \mathrm{nm}\) light directed perpendicular to the plane of the slits. What is the total number of complete bright fringes appearing between the two first-order minima of the diffraction pattern? (Do not count the fringes that coincide with the minima of the diffraction pattern.)

The wings of tiger beetles (Fig. \(36-41\) ) are colored by interference due to thin cuticle-like layers. In addition, these layers are arranged in patches that are \(60 \mu \mathrm{m}\) across and produce different colors. The color you see is a pointillistic mixture of thinfilm interference colors that varies with perspective. Approximately what viewing distance from a wing puts you at the limit of resolving the different colored patches according to Rayleigh's criterion? Use \(550 \mathrm{nm}\) as the wavelength of light and \(3.00 \mathrm{~mm}\) as the diameter of your pupil.

A diffraction grating having 180 lines/mm is illuminated with a light signal containing only two wavelengths, \(\lambda_{1}=400 \mathrm{nm}\) and \(\lambda_{2}=500 \mathrm{nm}\). The signal is incident perpendicularly on the grating. (a) What is the angular separation between the secondorder maxima of these two wavelengths? (b) What is the smallest angle at which two of the resulting maxima are superimposed? (c) What is the highest order for which maxima for both wavelengths are present in the diffraction pattern?

Find the separation of two points on the Moon's surface that can just be resolved by the 200 in. \((=5.1 \mathrm{~m})\) telescope at Mount Palomar, assuming that this separation is determined by diffraction effects. The distance from Earth to the Moon is \(3.8 \times 10^{5} \mathrm{~km}\). Assume a wavelength of \(550 \mathrm{nm}\) for the light.

(A) How far from grains of red sand must you be to position yourself just at the limit of resolving the grains if your pupil diameter is \(1.5 \mathrm{~mm}\), the grains are spherical with radius \(50 \mu \mathrm{m}\), and the light from the grains has wavelength \(650 \mathrm{nm} ?\) (b) If the grains were blue and the light from them had wavelength \(400 \mathrm{nm}\), would the answer to (a) be larger or smaller?

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