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A single slit is illuminated by light of wavelengths \(\lambda_{a}\) and \(\lambda_{b}\) chosen so that the first diffraction minimum of the \(\lambda_{a}\) component coincides with the second minimum of the \(\lambda_{b}\) component. (a) If \(\lambda_{b}=350 \mathrm{nm},\) what is \(\lambda_{a} ?\) For what order number \(m_{b}\) (if any) does a minimum of the \(\lambda_{b}\) component coincide with the minimum of the \(\lambda_{a}\) component in the order number (b) \(m_{a}=2\) and \((\mathrm{c}) m_{a}=3 ?\)

Short Answer

Expert verified
(a) \( \lambda_{a} = 700 \text{ nm} \). (b) \( m_{b} = 4 \). (c) \( m_{b} = 6 \).

Step by step solution

01

Understanding Diffraction Minima

The condition for a diffraction minimum in a single slit experiment is given by the equation \( a \sin \theta = m \lambda \), where \( a \) is the slit width, \( \theta \) is the angle of diffraction, \( m \) is the order of the minimum, and \( \lambda \) is the wavelength of the light. When two wavelengths coincide at a diffraction minimum, their conditions for minima match.
02

Set Condition for Coinciding Minima

We are given that the first minimum of wavelength \( \lambda_{a} \) coincides with the second minimum of \( \lambda_{b} \). Thus, we set the equations equal: \( a \sin \theta = 1 \cdot \lambda_{a} = 2 \cdot \lambda_{b} \). Further substitute \( \lambda_{b} = 350 \text{ nm} \).
03

Calculate Wavelength \( \lambda_{a} \)

From the condition \( \lambda_{a} = 2 \cdot \lambda_{b} \), substitute \( \lambda_{b} = 350 \text{ nm} \) to find \( \lambda_{a} = 2 \times 350 \text{ nm} = 700 \text{ nm} \).
04

Condition for Part (b) with \( m_{a} = 2 \)

For \( m_{a} = 2 \), we need \( a \sin \theta = 2 \cdot \lambda_{a} = m_{b} \cdot \lambda_{b} \). Substitute \( \lambda_{a} = 700 \text{ nm} \) and \( \lambda_{b} = 350 \text{ nm} \): \( 2 \times 700 \text{ nm} = m_{b} \times 350 \text{ nm} \). Solving for \( m_{b} \), we get \( 2m_{b} = 4 \Rightarrow m_{b} = 4 \).
05

Condition for Part (c) with \( m_{a} = 3 \)

For \( m_{a} = 3 \), similarly set \( a \sin \theta = 3 \cdot \lambda_{a} = m_{b} \cdot \lambda_{b} \). Substitute the known wavelengths: \( 3 \times 700 \text{ nm} = m_{b} \times 350 \text{ nm} \). Solving for \( m_{b} \), we get \( 3m_{b} = 6 \Rightarrow m_{b} = 6 \).
06

Summarize Solutions

For part (a), \( \lambda_{a} = 700 \text{ nm} \). For part (b), a diffraction minimum coincides at \( m_{b} = 4 \). For part (c), a minimum coincides at \( m_{b} = 6 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffraction Minima
In the fascinating world of optics, diffraction minima occur when waves like light bend around obstacles or pass through small openings. The term "diffraction minima" refers to specific points where the light intensity drops to zero due to interference of light waves. In a single slit diffraction experiment, these points are critical for understanding how light behaves. It is governed by the equation \( a \sin \theta = m \lambda \), where:
  • \( a \) is the slit width
  • \( \theta \) is the angle at which the light bends
  • \( m \) is an integer representing the order of the minimum (like 1st, 2nd, etc.)
  • \( \lambda \) is the wavelength of the light
When we talk about coinciding diffraction minima, it means two different sets of light conditions (like different wavelengths) align perfectly for minima at the same point. This happens when the diffraction condition for both sets are satisfied simultaneously. In the exercise, the first diffraction minimum of one wavelength happens to overlap with the second diffraction minimum of another wavelength.
Wavelength
Wavelength (\( \lambda \)) is a key characteristic of any wave, including light. It’s the distance between two consecutive peaks of the wave and determines many properties of the light, such as color. In optics, wavelengths are crucial in defining how light interacts with objects. They are typically measured in nanometers (nm) when dealing with visible light, which usually ranges from about 380 nm to 750 nm.

In the exercise, wavelength plays a pivotal role in calculating when diffraction minima coincide. Knowing one wavelength helps you predict others when certain diffraction conditions are met. For instance, given \( \lambda_b = 350 \text{ nm} \), you can determine \( \lambda_a \) by understanding the relationship between different diffraction order minima. It's found that \( \lambda_a = 700 \text{ nm} \) through the condition of \( 1 \lambda_a = 2 \lambda_b \).

Therefore, identifying and calculating the wavelength is essential to solving diffraction problems and predicting the light pattern generated by single slit diffraction.
Order of Diffraction Minimum
The order of diffraction minimum is indicated by the integer \( m \) in the diffraction condition equation \( a \sin \theta = m \lambda \). This integer determines which minimum you are observing. For example, \( m = 1 \) corresponds to the first minimum, \( m = 2 \) to the second, and so forth. These orders are essential because they indicate how many full waves fit into the slit width at the angle \( \theta \).

Knowing the order is crucial for bridging the gap between theory and practical observation in physics. In the given problem, matching the order of diffraction minima for two light wavelengths allows calculation of required wavelengths. In a scenario where the first order diffraction minimum of one wavelength matches with the second order of another, equations like \( 1 \cdot \lambda_a = 2 \cdot \lambda_b \) show them in harmony. For parts (b) and (c), other orders are considered, where \( m_a = 2 \) and \( m_a = 3 \) respectively, lead to corresponding values for \( m_b \).
  • For \( m_a = 2 \), \( m_b \) is found to be 4
  • For \( m_a = 3 \), \( m_b \) results in 6
This concept highlights how analyzing different orders of minima provides insights into the behavior of light and coherence between different wavelengths.

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Most popular questions from this chapter

A single-slit diffraction experiment is set up with light of wavelength \(420 \mathrm{nm}\), incident perpendicularly on a slit of width \(5.10 \mu \mathrm{m} .\) The viewing screen is \(3.20 \mathrm{~m}\) distant. On the screen, what is the distance between the center of the diffraction pattern and the second diffraction minimum?

In a double-slit experiment, the slit separation \(d\) is 2.00 times the slit width \(w\). How many bright interference fringes are in the central diffraction envelope?

A diffraction grating \(1.00 \mathrm{~cm}\) wide has 10000 parallel slits. Monochromatic light that is incident normally is diffracted through \(30^{\circ}\) in the first order. What is the wavelength of the light?

The wall of a large room is covered with acoustic tile in which small holes are drilled \(5.0 \mathrm{~mm}\) from center to center. How far can a person be from such a tile and still distinguish the individual holes, assuming ideal conditions, the pupil diameter of the observer's eye to be \(4.0 \mathrm{~mm},\) and the wavelength of the room light to be \(550 \mathrm{nm} ?\)

A beam of light consisting of wavelengths from \(460.0 \mathrm{nm}\) to \(640.0 \mathrm{nm}\) is directed perpendicularly onto a diffraction grating with 160 lines/mm. (a) What is the lowest order that is overlapped by another order? (b) What is the highest order for which the complete wavelength range of the beam is present? In that highest order, at what angle does the light at wavelength (c) \(460.0 \mathrm{nm}\) and (d) \(640.0 \mathrm{nm}\) appear? (e) What is the greatest angle at which the light at wavelength \(460.0 \mathrm{nm}\) appears?

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