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Visible light is incident perpendicularly on a grating with 315 rulings/mm. What is the longest wavelength that can be seen in the fifth-order diffraction?

Short Answer

Expert verified
The longest wavelength is approximately 635 nm.

Step by step solution

01

Understand the Diffraction Grating Formula

The primary equation for diffraction grating is given by \( d \sin \theta = m\lambda \), where \( d \) is the distance between the slits (inverse of the number of lines per meter), \( \theta \) is the angle of diffraction, \( m \) is the order of the diffraction, and \( \lambda \) is the wavelength. Because the light is incident perpendicularly and we want the longest wavelength, the angle \( \theta \) will be 90 degrees at its maximum.
02

Calculate the Grating Spacing

Given that the grating has 315 rulings per millimeter, convert the measurement to meters: 315 rulings/mm = 315,000 rulings/m. Thus, the distance \( d \) between the rulings is \( d = \frac{1}{315,000} \) meters.
03

Set Up the Equation for the Maximum Wavelength

For the maximum wavelength at the fifth order diffraction, use \( m = 5 \). Plug into the equation \( d \sin \theta = m\lambda \) which becomes \( \lambda = \frac{d \sin 90}{5} \). Since \( \sin 90 = 1 \), this simplifies to \( \lambda = \frac{d}{5} \).
04

Solve for the Longest Wavelength

Substitute \( d = \frac{1}{315,000} \) meters into the equation: \( \lambda = \frac{1}{5 \times 315,000} \). Simplifying this gives \( \lambda \approx 6.35 \times 10^{-7} \) meters, which is the longest wavelength.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Wavelength
Wavelength is a fundamental property of waves, describing the distance between successive crests of a wave. In the context of light waves, it determines the color in the visible spectrum. The wavelength of visible light ranges approximately between 400 nm (violet) and 700 nm (red).
Diffraction, a common wave phenomenon, provides a means to measure this wavelength precisely. It occurs when a wave encounters an obstacle or a slit that it can bend around, like in a diffraction grating. This grating consists of many small slits that break up the light wave into its component wavelengths through interference.
When each slit in the grating acts as a new point of emission, the overlap of the new wave fronts can create a constructive interference at specific angles, known as diffraction angles. These angles are used to determine the wavelength using the diffraction grating equation:
  • \( d \sin \theta = m\lambda \)
where \( \lambda \) is the wavelength, \( d \) is the grating spacing, \( \theta \) is the angle, and \( m \) is the diffraction order.
Exploring Diffraction Order
In diffraction, the order refers to how many wavelengths fit into the path difference between light waves from adjacent slits. The first-order diffraction (\( m = 1 \)) means one full wavelength fits, creating the first maximum intensity spot on either side of the central maximum.
  • Higher diffraction orders correspond to larger integer values \( m \), which indicate points where multiple whole wavelengths create constructive interference.
As the order increases, these maxima spread out, occurring at more significant angles in the diffraction pattern. For instance, the fifth-order diffraction (\( m = 5 \)) represents a condition where five wavelengths cause constructive interference.
Higher orders can mean reduced intensity and can differ slightly in color, but this provides us the fascinating ability to observe different features of light waves. The equation for diffraction grating uses the order \( m \) to locate these maxima precisely at corresponding wavelengths.
Importance of Grating Spacing
Grating spacing, denoted by \( d \), is the distance between two consecutive slits on a diffraction grating. It profoundly influences the diffraction pattern observed.
  • Distance is the inverse of the number of slits per unit length, so more slits mean smaller spacing \( d \).
Grating spacing is pivotal because it determines how closely spaced the diffraction angles are. As per the diffraction grating law, \( d\sin\theta = m\lambda \), a small spacing results in a larger angle for each order of diffraction, which spreads out the spectra more.For example, in our exercise, knowing that there are 315 rulings per millimeter or 315,000 per meter, we calculated the spacing as \( d = \frac{1}{315,000} \) meters. This small spacing allows precise separation of light into its component colors, enabling more detailed spectral analysis. Understanding and manipulating grating spacing is key in applications like spectroscopy and laser technology.

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Most popular questions from this chapter

Monochromatic light of wavelength \(441 \mathrm{nm}\) is incident on a narrow slit. On a screen \(2.00 \mathrm{~m}\) away, the distance between the second diffraction minimum and the central maximum is \(1.50 \mathrm{~cm}\). (a) Calculate the angle of diffraction \(\theta\) of the second minimum. (b) Find the width of the slit.

If you double the width of a single slit, the intensity of the central maximum of the diffraction pattern increases by a factor of \(4,\) even though the energy passing through the slit only doubles. Explain this quantitatively.

If you look at something \(40 \mathrm{~m}\) from you, what is the smallest length (perpendicular to your line of sight) that you can resolve, according to Rayleigh's criterion? Assume the pupil of your eye has a diameter of \(4.00 \mathrm{~mm}\), and use \(500 \mathrm{nm}\) as the wavelength of the light reaching you.

(A) A circular diaphragm \(60 \mathrm{~cm}\) in diameter oscillates at a frequency of \(25 \mathrm{kHz}\) as an underwater source of sound used for submarine detection. Far from the source, the sound intensity is distributed as the diffraction pattern of a circular hole whose diameter equals that of the diaphragm. Take the speed of sound in water to be \(1450 \mathrm{~m} / \mathrm{s}\) and find the angle between the normal to the diaphragm and a line from the diaphragm to the first minimum. (b) Is there such minimum for a source having an (audible) freguency of \(1.0 \mathrm{kHz}\) ?

Light containing a mixture of two wavelengths, 500 and \(600 \mathrm{nm},\) is incident normally on a diffraction grating. It is desired (1) that the first and second maxima for each wavelength appear at \(\theta \leq 30^{\circ},\) (2) that the dispersion be as high as possible, and (3) that the third order for the \(600 \mathrm{nm}\) light be a missing order. (a) What should be the slit separation? (b) What is the smallest individual slit width that can be used? (c) For the values calculated in (a) and (b) and the light of wavelength \(600 \mathrm{nm}\), what is the largest order of maxima produced by the grating?

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