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Light containing a mixture of two wavelengths, 500 and \(600 \mathrm{nm},\) is incident normally on a diffraction grating. It is desired (1) that the first and second maxima for each wavelength appear at \(\theta \leq 30^{\circ},\) (2) that the dispersion be as high as possible, and (3) that the third order for the \(600 \mathrm{nm}\) light be a missing order. (a) What should be the slit separation? (b) What is the smallest individual slit width that can be used? (c) For the values calculated in (a) and (b) and the light of wavelength \(600 \mathrm{nm}\), what is the largest order of maxima produced by the grating?

Short Answer

Expert verified
(a) 1800 nm, (b) 600 nm, (c) Order 3.

Step by step solution

01

Analyze the Diffraction Criteria

The problem asks for three conditions: (1) maxima for each wavelength at \( \theta \leq 30^{\circ} \), (2) high dispersion, and (3) the third order for \( 600 \text{ nm} \) should be a missing order. We will begin by analyzing the given information and constraints of diffraction gratings. The equation for diffraction maxima for a grating is given by \( d \sin \theta = m \lambda \), where \( d \) is the grating spacing, \( m \) is the order of diffraction, and \( \lambda \) is the wavelength.
02

Determine Maximum Orders with Angle Criterion

We use the equation \( d \sin 30^{\circ} = m \lambda \) for each wavelength to find \( m_1 \) for \( 500 \text{ nm} \) and \( m_2 \) for \( 600 \text{ nm} \).\( d \sin 30^{\circ} = \frac{d}{2}, \) hence:\[ m_1 \times 500 = \frac{d}{2}, \quad m_2 \times 600 = \frac{d}{2}. \]From the equation \( m_1 \leq 2 \) (since beyond that, the angle exceeds 30 degrees) and similarly for \( m_2 \).
03

Calculate Slit Separation for Missing Order Criteria

To have the third order of 600 nm light missing, \( d \) must satisfy \( d = m\lambda_1 \) for some integer \( m \) such that the third order of \( 600 \text{ nm} \) satisfies \( d \times 600 \times 3 = n \lambda \) where \( n \) is not an integer. Solving these conditions gives:\[ d = 3 \times 600 \text{ nm} = 1800 \text{ nm}.\]
04

Determine Individual Slit Width

The slit width \( a \) must ensure high dispersion, which implies small slit widths to maximize resolution and separation of orders. Another criterion is that it ensures missing orders: for missing third order,\[ \frac{a}{d} = \frac{1}{3}.\]Thus,\[ a = \frac{1}{3} \times 1800 \text{ nm} = 600 \text{ nm}.\]
05

Find Largest Order for 600 nm Light

For the largest order of maxima, solve \( d \sin 90^{\circ} = m \, 600 \) to find the maximum order \( m_\text{max} \):\[ m_\text{max} \times 600 \text{ nm} = 1800 ,\]\[ m_\text{max} = 1800 / 600 = 3.\]
06

Compile Results

The calculated slit separation is 1800 nm, the smallest slit width is 600 nm, and the largest order of maxima for 600 nm light is 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength
The concept of wavelength is fundamental when discussing diffraction gratings. A wavelength is the distance between successive peaks of a wave, be it light, sound, or another type of wave. In the context of diffraction gratings, different wavelengths correspond to different colors of light. For example, light at 500 nm could appear green, while light at 600 nm might appear orange.

The diffraction grating's role is to separate these different wavelengths so they can be analyzed or used in various scientific applications. This separation happens because different wavelengths are bent at different angles when they pass through the grating, a phenomenon that is dependent on the grating's physical structure.

In the exercise, we encounter two wavelengths, 500 nm and 600 nm, which will diffract and produce maxima at specific angles. Our goal is to ensure that these angles are less than or equal to 30 degrees for both the first and second orders of diffraction.
Maxima
In the study of diffraction gratings, **maxima** refer to the points of maximum intensity in the diffraction pattern. These are the bright spots observed when light is diffracted, resulting from constructive interference of the light waves.

The condition for maxima in a diffraction grating is described by the formula \[ d \sin \theta = m \lambda \] where \( d \) is the separation between slits, \( \theta \) is the diffraction angle, \( m \) is the order number, and \( \lambda \) is the wavelength. You'll find that these maxima occur at certain specific angles, depending on the wavelength and the grating's characteristics.

For our wavelengths of 500 nm and 600 nm, we seek to find maxima at angles up to 30 degrees for their first and second orders. By understanding how each wavelength interacts with the grating, one can predict where these maxima will occur.
Slit Separation
**Slit separation**, often denoted by \( d \), is a critical parameter in a diffraction grating. It defines the distance between adjacent slits in the grating. This spacing affects how the different wavelengths of light will spread out, or diffract, as they pass through the grating.
  • The larger the slit separation, the closer the maxima will appear.
  • The smaller the slit separation, the more spread out the light will be, resulting in a wider angle for any given order of diffraction.

For our problem, in order to meet the conditions of having maxima at \( \theta \leq 30^{\circ} \) and to create a missing order at the third order for 600 nm light, the slit separation must be calculated precisely. It is found to be 1800 nm. This value allows the first two orders for both 500 nm and 600 nm light to appear at less than 30 degrees while ensuring the third order for 600 nm is missing.
Missing Order
A **missing order** refers to a situation where no intensity peak, or maxima, is observed at a certain order of diffraction. This occurs due to the specific conditions that cause destructive interference, effectively cancelling out that order.

In a diffraction grating, missing orders can be deliberately created by the design of the grating. For our problem, the missing order happens because the conditions cause the third order maxima for 600 nm light to be suppressed.

To achieve this, the slit separation \( d = 1800 \) nm must coincide with specific integer multiples of the wavelength (other than the intended missing order). Given our light of 600 nm, the condition is formulated as \( d \cdot 3 = n \lambda \) for a non-integer \( n \). This results in complete cancellation for that order and thus no light maxima can be observed, effectively removing that diffraction pattern order.

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Most popular questions from this chapter

An \(x\) -ray beam of wavelength \(A\) undergoes first-order reflection (Bragg law diffraction) from a crystal when its angle of incidence to a crystal face is \(23^{\circ}\), and an x-ray beam of wavelength 97 pm undergoes third-order reflection when its angle of incidence to that face is \(60^{\circ} .\) Assuming that the two beams reflect from the same family of reflecting planes, find (a) the interplanar spacing and (b) the wavelength \(A\).

A diffraction grating with a width of \(2.0 \mathrm{~cm}\) contains 1000 lines/cm across that width. For an incident wavelength of \(600 \mathrm{nm},\) what is the smallest wavelength difference this grating can resolve in the second order?

If you look at something \(40 \mathrm{~m}\) from you, what is the smallest length (perpendicular to your line of sight) that you can resolve, according to Rayleigh's criterion? Assume the pupil of your eye has a diameter of \(4.00 \mathrm{~mm}\), and use \(500 \mathrm{nm}\) as the wavelength of the light reaching you.

In June \(1985,\) a laser beam was sent out from the Air Force Optical Station on Maui, Hawaii, and reflected back from the shuttle \(D i s-\) covery as it sped by \(354 \mathrm{~km}\) overhead. The diameter of the central maximum of the beam at the shuttle position was said to be \(9.1 \mathrm{~m}\) and the beam wavelength was \(500 \mathrm{nm}\). What is the effective diameter of the laser aperture at the Maui ground station? (Hint: A laser beam spreads only because of diffraction; assume a circular exit aperture.)

Light of wavelength \(500 \mathrm{nm}\) diffracts through a slit of width \(2.00 \mu \mathrm{m}\) and onto a screen that is \(2.00 \mathrm{~m}\) away. On the screen, what is the distance between the center of the diffraction pattern and the third diffraction minimum?

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