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At timet = 0and at position x = 0 malong a string, a traveling sinusoidal wave with an angular frequency of 440 rad/shas displacement y=+4.5mmand transverse velocityu=0.75m/s . If the wave has the general formy(x,t)=ymsin(kx-Ó¬t+Ï•) , what is phase constant Ï•?

Short Answer

Expert verified

Phase constant Ï• is 1.2 rad

Step by step solution

01

Given data

Angular frequency isÓ¬=440rad/s

Displacementy=+4.5mm

Transverse velocity isu=-0.75m/s

Wave equation is yx,t=ymsinkx-Ó¬t+Ï•

02

Understanding the concept of wave motion

We use the concept of wave motion. We can differentiate the given equation for velocity and take the ratio of displacement by velocity. At initial values of x and t, we get the equation for, plugging the given values, we get the value for phase constant.

Formulae:

The velocity of the body in motion, v=dvdt........1

03

Calculation of phase constant

We know that velocity of the wave using equation (1) is given as:
ux,t=dydt=dymsinkx-Ӭt+ϕdt=-ymӬcoskx-Ӭt+ϕ

We know the equation of wave is given as:

yx,t=ymsinkx-Ó¬t+Ï•

We can take the ratio ofand

yx,tux,t=ymsinkx-Ӭt+ϕ-ymӬcoskx-Ӭt+ϕyx,tux,t=sinkx-Ӭt+ϕ-Ӭcoskx-Ӭt+ϕ=tankx-Ӭt+ϕӬ

Plugging the given values in the above equation, we get

4.5-0.75=tankx-Ӭt+ϕӬankx-Ӭt+ϕ=4.5×10-3×4400.75kx-Ӭt+ϕ=tan-12.640kx-Ӭt+ϕ=69.25°

For x = 0 then t = 0 , we get the value of phase constant as:

ϕ=69.25°=69.25°×πrad180°=1.2rad

Hence, the value of phase constant is 1.2rad.

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