91Ó°ÊÓ

1. Speed of the wave, v = 240 m/s .
2. The wavelength of the wave, 13 ms .

The transverse speed of the wave is the displacement of the wave in the given period of its oscillation, and the period is given by the reverse of the frequency of the wave. Thus, using the given formulae with the given data, the required values can be calculated.

Formulae:

The speed of the wave,

$v=f\mathrm{λ}$ (i)

Where, f is the frequency and$\mathrm{λ}$ is the wavelength of the wave.

The period of oscillation of the wave,

$T=\frac{1}{f}$ (ii)

Using the given data in equation (i), the frequency of the wave can be given as follows:

$$\begin{gathered} f=\frac{240\mathrm{m}/\mathrm{s}}{3.2\mathrm{m}} \\ =75\mathrm{Hz} \end{gathered}$$

Hence, the value of the frequency is 75 Hz .

Using the given data in equation (ii), the period of the oscillation can be given as follows:

$$\begin{gathered} T=\frac{1}{75\mathrm{Hz}} \\ =0.0133\mathrm{s} \\ =13.3×{10}^{-3}\mathrm{s} \\ ≈13\mathrm{ms} \end{gathered}$$

Hence, the value of the period is 13 ms .