/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q42P A string under tension Ï„i oscil... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A string under tension τi oscillates in the third harmonic at frequency f3, and the waves on the string have wavelength λ3. If the tension is increased to τf=4τi and the string is again made to oscillate in the third harmonic. What then are (a) the frequency of oscillation in terms of f3 and (b) the wavelength of the waves in terms of λ3?

Short Answer

Expert verified
  1. The frequency in oscillation is 2f3
  2. The wavelength of the waves is λ3

Step by step solution

01

Given data

The tension is increased to τf=4τi.

02

Understanding the concept of resonant frequency

By using the formulas for resonant frequency fand the speed v of the wave, we can find the frequency of oscillation in terms of and by using the formula for the new wavelength we can find the wavelength of the waves in terms of .

Formula:

The resonant frequency of a wave,f=vλ......(1)

The speed of wave, v=τμ.........(2)

The nth frequency of a wave, fn=nv2L.....(3)

03

Step 3(a): Calculation for the frequency in oscillation

Substituting the equation (2) in equation (3), we get the nth frequency as:

fn=n2L×τμ

Hence, the third frequency is given as:

f3=32L×τiμ......(4)

When,τf=4τi, using this in equation (4),we get the new frequency is given as:

f'3=32L×τiμ=232L×τiμ(∵τf=4τi)=2f3

Hence, the value of the new frequency is 2f3

04

Step 4(b): Calculation for the wavelength

Using equation (1), we can get the new wavelength as given:

λ'3=v'f'3=τiμ2f3(∵usingequation(2))=2τiμ2f3(∵f3'=f3andτf=4τi)=vf3=λ3

Hence, the value of new wavelength is λ3

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If you start with two sinusoidal waves of the same amplitude traveling in phase on a string and then somehow phase-shift one of them by 5.4wavelengths, what type of interference will occur on the string?

Use the wave equation to find the speed of a wave given in terms of the general function: h(x,t)

localid="1660990709658" y(x,t)=(4.00mm)h[(30m-1)x+(6.0s-1)t].

The following two waves are sent in opposite directions on a horizontal string so as to create a standing wave in a vertical plane:

y1(x,t)=(6.00mm)sin(4.00Ï€x-400Ï€t)y2(x,t)=(6.00mm)sin(4.00Ï€³æ+400Ï€³Ù)

within X meters andin seconds. An antinode is located at point A. In the time interval that point takes to move from maximum upward displacement to maximum downward displacement, how far does each wave move along the string?

Strings Aand Bhave identical lengths and linear densities, but string Bis under greater tension than string A. Figure 16-27 shows four situations, (a) through (d), in which standing wave patterns exist on the two strings. In which situations is there the possibility that strings Aand Bare oscillating at the same resonant frequency?

These two waves travel along the same string:

y1(x,t)=(4.60mm)sin(2Ï€³æ-400Ï€³Ù)y2(x,t)=(5.60mm)sin(2Ï€³æ-400Ï€³Ù+0.80Ï€°ù²¹»å)

What is the amplitude (a) and (b) what is the phase angle (relative to wave 1) of the resultant wave? (c) If a third wave of amplitude 5.00 mmis also to be sent along the string in the same direction as the first two waves, what should be its phase angle in order to maximize the amplitude of the new resultant wave?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.