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A gas is to be expanded from initial state i to final state f along either path 1or path 2on a PV diagram. Path1 consists of three steps: an isothermal expansion (work is40 Jin magnitude), an adiabatic expansion (work isin magnitude), and another isothermal expansion (work is20 Jin magnitude). Path2 consists of two steps: a pressure reduction at constant volume and an expansion at constant pressure. What is the change in the internal energy of the gas along path 2?

Short Answer

Expert verified

The change in internal energy along path 2 is −20 J.

Step by step solution

01

Write the given data from the question:

  • Isothermal expansionW=40 J
  • Adiabatic expansion,W=20 J
  • Isothermal expansion,W=30J
02

Understanding the concept

The expression for the heat from the first law of thermodynamics is given by,

Q=W+ΔU

Here Q is the heat required, W is the work done, ΔUis the change in internal energy.

So, the first law of thermodynamics gives the relation between heat, work and internal energy.

03

Calculate the change in internal energy of the gas

For path 1:

As internal energy is a state function for an isothermal process,dU=0.

For adiabatic process,dQ=0,

Therefore,dU=-dW

Therefore, net change in internal energy of path 1 is

dU=−20 J

But, internal energy is independent of the path, so change in internal energy along path 2 is the same as path 1.

dU=−20 J

Therefore the change in internal energy along path 2 is−20 J .

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