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We give70 Jas heat to a diatomic gas, which then expands at constant pressure. The gas molecules rotate but do not oscillate. By how much does the internal energy of the gas increase?

Short Answer

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Step by step solution

01

Given data

Heat energy given to a diatomic gas isQ=70J

02

Understanding the concept

The expression for the amount of energy transferred to the gas is given by,

Q=nCVΔT

Here Q is the amount of energy transferred to gas,n is the number of moles, Cvis the specific heat capacity at constant volume and ΔTis the temperature difference.

03

Calculate by how much the internal energy of the gas increases

ΔEint=nCVΔT

But, for diatomic gas,CV=52R

Hence,

ΔEint=52nRΔT …… (i)

Also,Q=nCPΔT

But, for diatomic gasCP=72R

Hence,

Q=72nRΔTnRΔT=27Q

Substitute27Qfor nRΔTinto the equation (i)

ΔEint=5227Q

Substitute70 J for Q into the above equation,

⇒ΔEint=50 J

Therefore, the increase in the internal energy is50J.

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