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In Fig.10-49, a small disk of radius r=2.00cmhas been glued to the edge of a larger disk of radius R=4.00cmso that the disks lie in the same plane. The disks can be rotated around a perpendicular axis through pointOat the center of the larger disk. The disks both have a uniform density (mass per unit volume) of1.40×103kg/m2and a uniform thickness of 5.00mm. What is the rotational inertia of the two-disk assembly about the rotation axis through O?

Short Answer

Expert verified

The rotational inertia of the two-disc assembly about the rotation axis through O is

6.16×10-5kgm2

Step by step solution

01

Given

  1. Thickness of the discd=5.0×10-3m
  2. Radius of big discR=0.04m
  3. Radius of small discr=0.02m
  4. Density of materialÒÏ=1400kg/m3
  5. Rotational inertia of wheelI=0.050kgm2
  6. Magnitude of forceP=3.0N
02

Understanding the concept

Use the parallel axis theorem to obtain the rotational inertia of the two-disc assembly.

Formula:

I=12mR2+md2m=ÒÏv=ÒÏÏ€r2d

03

Calculate the rotational inertia of the two-disk assembly about the rotation axis through O 

For the rotational inertia of the two-disc assembly about the rotation axis through ,

I=12MR2+12mr2+mr+R2I=12ÒÏÏ€R2dR2+12ÒÏÏ€r2dr2+ÒÏÏ€r2dr+R2I=ÒÏÏ€d12R4+12r4+r2r+R2I=1400kg/m3)Ï€(5.0×10-3m120.04m4+120.02m4+0.02m20.02m+0.04m2I=6.16×10-5kg.m2Therefore, the rotational inertia of the two-disc assembly about the rotation axis through O is6.16×10-5kgm2

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