/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q36P Figure 10-34a聽shows a disk that... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Q36P (page 288)

Figure 10-34ashows a disk that can rotate about an axis at a radial distance hfrom the center of the disk. Figure 10-34b gives the rotational inertia lof the disk about the axis as a function of that distance h, from the center out to the edge of the disk. The scale on the laxis is set by lA=0.050kg.m2andlB=0.050kg.m2. What is the mass of the disk?

Short Answer

Expert verified

The mass of the disk is, 2.5kg

Step by step solution

01

Understanding the given information

  1. Moment of inertia at hA=0mis lA=0.050kg.m2
  2. Moment of inertia at hB=0.2mis, lB=0.150kg.m2.
02

Concept and Formula used in the given question

By applying the parallel axis theorem for two values of moment of inertia as given in the graph we will get two equations. By solving them we can find mass of the disk.

Parallel axis theorem,

l=lcom+mh2

03

Calculation for the mass of the disk

To calculate mass of the disk we will apply Parallel axis theorem for lA and lB

lA=lcom+mhA2 鈥�(1)

lB=lcom+mhB2 鈥�(2)

lcom is the moment of inertia of the disk about its center of mass.

Subtracting equation (2) from (1)

lB-lA=mhB2-hA2m=lB-lAhB2-hA2

Substitute all the value in the above equation.

We can use the values of hA,hB from the given graph

m=0.150kg.m2-0.050kg.m20.2m2-om2=2.5kg

Hence the mass of the disk is, 2.5kg.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a judo foot-sweep move, you sweep your opponent鈥檚 left foot out from under him while pulling on his gi (uniform) toward that side. As a result, your opponent rotates around his right foot and onto the mat. Figure 10鈭�44shows a simplified diagram of your opponent as you face him, with his left foot swept out. The rotational axis is through point O. The gravitational force F鈫�g on him effectively acts at his center of mass, which is a horizontal distanced=28鈥塩尘 from point O. His mass is 70Kg, and his rotational inertia about point O is 65鈥塳驳.尘2.What is the magnitude of his initial angular acceleration about point O if your pull F鈫�a on his gi is (a) negligible and (b) horizontal with a magnitude of 300Nand applied at height h=1.4鈥尘 ?

Figure 10-25ais an overhead view of a horizontal bar that can pivot; two horizontal forces act on the bar, but it is stationary. If the angle between the bar and F鈫�2is now decreased from 90掳and the bar is still not to turn, should F鈫�2be made larger, made smaller, or left the same?

Two uniform solid spheres have the same mass of1.65 kg, but one has a radius of0.226 mand the other has a radius of. Each can rotate about an axis through its center. (a) What is the magnitudeof the torque required to bring the smaller sphere from rest to an angular speed of317 rad/sin15.5 s? (b) What is the magnitudeof the force that must be applied tangentially at the sphere鈥檚 equator to give that torque? What are the corresponding values of (c)蟿and (d)for the larger sphere?

The rigid object shown in Fig.10-62consists of three ballsand three connecting rods, withM=1.6kg,L=0.60mand胃=30掳. The balls may be treated as particles, and the connecting rods have negligible mass. Determine the rotational kinetic energy of the object if it has an angular speed of1.2鈥塺补诲/蝉about (a) an axis that passes through point P and is perpendicular to the plane of the figure and (b) an axis that passes through point P, is perpendicular to the rod of length2L, and lies in the plane of the figure.

The uniform solid block in Fig 10-38has mass 0.172kg and edge lengths a = 3.5cm, b = 8.4cm, and c = 1.4cm. Calculate its rotational inertia about an axis through one corner and perpendicular to the large faces.
See all solutions

Recommended explanations on Physics Textbooks

Physics of Motion

Read Explanation

Electricity and Magnetism

Read Explanation

Dynamics

Read Explanation

Translational Dynamics

Read Explanation

Measurements

Read Explanation

Circular Motion and Gravitation

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.