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A high-wire walker always attempts to keep his center of mass over the wire (or rope). He normally carries a long, heavy pole to help: If he leans, say, to his right (his com moves to the right) and is in danger of rotating around the wire, he moves the pole to his left (its com moves to the left) to slow the rotation and allow himself time to adjust his balance. Assume that the walker has a mass of 70.0kgand a rotational inertia of about the wire.What is the magnitude of his angular acceleration about the wire if his com is 5.0cmto the right of the wire and (a) he carries no pole and (b) the 14.0kgpole he carries has its com 10 cm to the left of the wire?

Short Answer

Expert verified
  1. The magnitude of angular acceleration about the wire if the walker’s center of mass is5.0cm to the right of the wire and carries no poleis2.3rads2
  2. The magnitude of angular acceleration about the wire if the walker’s com is 5.0cmto the right of the wire and the 14.0kgpole he carries, its com is 10 cm to the left of the wire is1.4rad/s2

Step by step solution

01

Explanation the Concept:

As the torque is the product of the force and distance from the pivot to the point of application of force, we can use the formula for torque in terms of angular acceleration and moment of inertia and in terms of distance and force to find the magnitude of angular acceleration. Here, this force is the gravitational force of the walker’s center of mass.

02

Given

  1. Mass of walkerM=70.0kg
  2. Rotational inertia of walkerI=15.0kg.m2
  3. Distancer=5.0cm=5.0×10-2m
03

Calculation

a. For torque in terms of angular acceleration and moment of inertia,

τ=Iα

And, in terms of distance and force,

Ï„=rF

Therefore,

Iα=rF

But,F=mgso,

Iα=rmg

α=rmgI

α=5.0×10-2m70.0kg9.8m/s215kgm2

α=2.3rad/s2

Therefore, the magnitude of angular acceleration about the wire if his com is 5.0cmto the right of the wire and carries no pole is 2.3rad/s2

b. As the walker carries a pole, torque due to the gravitational force through the pole’s center of mass opposes the torque due to the gravitational force that passes through the walker’s center of mass. Therefore,

τnet=Iα

α=τnetI

α=τwalker-τpoleI

α=rcommg-r'm'gI

α=5.0×10-2m70.0kg9.8ms2-10×10-2m14.0kg9.8ms215kgm2

α=1.4rads2

Therefore, magnitude of angular acceleration about the wire if his com is to the right of the wire and the pole he carries its com is 10 cm to the left of the wire is

1.4rads2

Final Statement:

We can find the magnitude of angular acceleration about the wire using the formula for torque in terms of angular acceleration and moment of inertia and in terms of distance and force.

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