/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q75P If we intercept an electron havi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If we intercept an electron having total energy of 1533 MeV that came from Vega, which is 26 ly from us, how far in light-years was the trip in the rest frame of the electron?

Short Answer

Expert verified

In the rest frame of the electron, the distance travelled by the electron from Vega to earth is 77896 light-years.

Step by step solution

01

Lorentz factor.

The result of 2nd postulate of the special theory of relativity is that the clocks run slower for a moving object when measured from a rest frame. The factor by which the clock is running differently is called the Lorentz factor.

The relativistic kinetic energy relation is given by

K=mec2γ-1

Where meis the electron’s rest mass, and ,γis the Lorentz factor. Using this relation to determine the Lorentz factor,

γ=Kmec2+1=1533×106×1.6×10-19J9.1×10-31kg(3×108m/s)2+1=2995+1=2996

We know that the Lorentz factor is expressed in terms of speed parameter (β=v/c)as,

γ=11-β2β=1-1γ2=1-129962=0.9999

Hence the electron is traveling at a speed of 0.9999c.

02

Length contraction

The length of an object measured in the object’s inertial reference frame is called proper length. When the length of this object is measured in any other inertial frame moving at relative speed is always shorter than the proper length. This is known as length contraction.

L=Lo1-β2=Loγ

Here, the length measured from the earth’s frame is 26 ly, and the Lorentz factor is found to have a value of 2996.The proper distance, i.e., the distance measured from the electron’s reference frame between vegan and earth, is

L=LoγLo=γL=299626ly=77896ly

In the rest frame of the electron, the distance travelled by the electron from Vega to earth is 77896 light-years.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a high-energy collision between a cosmic-ray particle and a particle near the top of Earth’s atmosphere, 120 km above sea level, a pion is created. The pion has a total energy E of 1.35×105MeVand is travelling vertically downward. In the pion’s rest frame, the pion decays 35.0 ns after its creation. At what altitude above sea level, as measured from Earth’s reference frame, does the decay occur? The rest energy of a pion is 139.6 MeV.

Space cruisers A and B are moving parallel to the positive direction of an x axis. Cruiser A is faster, with a relative speed of v=0.900c, and has a proper length of L=200m. According to the pilot of A, at the instant (t = 0) the tails of the cruisers are aligned, the noses are also. According to the pilot of B, how much later are the noses aligned?

Figure 37-21 shows one of four star cruisers that are in a race. As each cruiser passes the starting line, a shuttle craft leaves the cruiser and races toward the finish line. You, judging the race, are stationary relative to the starting and finish lines. The speeds vc of the cruisers relative to you and the speeds of the shuttle craft relative to their respective starships are, in that order, (1) 0.70c, 0.40c; (2) 0.40c, 0.70c; (3) 0.20c, 0.90c; (4) 0.50c, 0.60c. (a) Rank the shuttle craft according to their speeds relative to you, greatest first. (b) Rank the shuttle craft according to the distances their pilots measure from the starting line to the finish line, greatest first. (c) Each starship sends a signal to its shuttle craft at a certain frequency f0 as measured on board the starship. Rank the shuttle craft according to the frequencies they detect, greatest first.


To eight significant figures, what is speed parameter if the Lorentz factor γ is (a) 1.010 000 0, (b) 10.000 000, (c) 100.000 00, and (d) 1000.000 0?

Superluminal jets. Figure 37-29a shows the path taken by a knot in a jet of ionized gas that has been expelled from a galaxy. The knot travels at constant velocity v→ at angleθ from the direction of Earth. The knot occasionally emits a burst of light, which is eventually detected on Earth. Two bursts are indicated in Fig. 37-29a, separated by timet as measured in a stationary frame near the bursts. The bursts are shown in Fig. 37-29b as if they were photographed on the same piece of film, first when light from burst 1 arrived on Earth and then later when light from burst 2 arrived. The apparent distanceD¯app traveled by the knot between the two bursts is the distance across an Earth-observer’s view of the knot’s path. The apparent timeT¯app between the bursts is the difference in the arrival times of the light from them. The apparent speed of the knot is then V¯app=D¯app/T¯app. In terms of v, t, andθ , what are (a)D¯app and (b)T¯app ? (c) EvaluateV¯app forv=0.980c and θ=30.0∘. When superluminal (faster than light) jets were first observed, they seemed to defy special relativity—at least until the correct geometry (Fig. 37-29a) was understood.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.