/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q76P The total energy of a proton pas... [FREE SOLUTION] | 91影视

91影视

The total energy of a proton passing through a laboratory apparatus is 10.611-nJ. What is its speed parameter ? Use the proton mass given in Appendix B under 鈥淏est Value,鈥 not the commonly remembered rounded number.

Short Answer

Expert verified

The speed parameter is 0.9898856096c

Step by step solution

01

Relativistic Total energy

The total energy of an object is the sum of its rest mass energy, kinetic energy if its moving, and potential energy if it is under some force.The total relativistic energy of an object moving at constant velocity will be expressed as

E=mc2

Where, is the Lorentz factor, and m, is the rest mass of the object. Here in the question, it is asked to use the best value for the proton鈥檚 mass1.67262163710-27kg.

Inserting these values in the above equation to get,

10.61110-9J=1.67262163710-27kg3108m/s210.61110-9J=1.50535947310-11kgm2/s2=10.61110-91.50535947310-117.048814712

02

Lorentz factor

The result of 2nd postulate of the special theory of relativity is that the clocks run slower for a moving object when measured from a rest frame. The factor by which the clock is running differently is called the Lorentz factor.

The expression for Lorentz factor is

=11-2

Here is the speed parameterv/c. Inserting the value of the Lorentz factor in this expression

=11-2=1-12=1-17.0488147122=0.9898856096

The speed parameter thus obtained up to 10 significant values because the best value of proton鈥檚 mass is given in 10 significant values is asked to be considered.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Fig. 37-9, observer S detects two flashes of light. A big flash occurs at x1=1200mand , slightly later, a small flash occurs at x2=480m. The time interval between the flashes ist=t2-t1. What is the smallest value of t for which observer S' will determine that the two flashes occur at the same x' coordinate?

In Fig. 37-35, three spaceships are in a chase. Relative to an x-axis in an inertial frame (say, Earth frame), their velocities are vA=0.900c, vB, and vc=0.900c. (a) What value of vBis required such that ships A and C approach ship B with the same speed relative to ship B, and (b) what is that relative speed?

The car-in-the-garage problem. Carman has just purchased the world鈥檚 longest stretch limo, which has a proper length of Lc=30.5鈥尘. In Fig. 37-32a, it is shown parked in front of a garage with a proper length of Lg=6.00鈥尘. The garage has a front door (shown open) and a back door (shown closed).The limo is obviously longer than the garage. Still, Garageman, who owns the garage and knows something about relativistic length contraction, makes a bet with Carman that the limo can fit in the garage with both doors closed. Carman, who dropped his physics course before reaching special relativity, says such a thing, even in principle, is impossible.

To analyze Garageman鈥檚 scheme, an xc axis is attached to the limo, with xc=0 at the rear bumper, and an xg axis is attached to the garage, with xg=0 at the (now open) front door. Then Carman is to drive the limo directly toward the front door at a velocity of 0.9980c(which is, of course, both technically and financially impossible). Carman is stationary in the xcreference frame; Garageman is stationary in the role="math" localid="1663064422721" Xgreference frame.

There are two events to consider. Event 1: When the rear bumper clears the front door, the front door is closed. Let the time of this event be zero to both Carman and Garageman: tg1=tc1=0. The event occurs at xg=xc=0. Figure 37-32b shows event 1 according to the xg reference frame. Event 2: When the front bumper reaches the back door, that door opens. Figure 37-32c shows event 2 according to the xg reference frame.

According to Garageman, (a) what is the length of the limo, and what are the spacetime coordinates (b) xg2 and (c) tg2 of event 2? (d) For how long is the limo temporarily 鈥渢rapped鈥 inside the garage with both doors shut? Now consider the situation from the xc reference frame, in which the garage comes racing past the limo at a velocity of 0.9980c. According to Carman, (e) what is the length of the passing garage, what are the spacetime coordinates (f) Xc2and (g) tc2 of event 2, (h) is the limo ever in the garage with both doors shut, and (i) which event occurs first? (j) Sketch events 1 and 2 as seen by Carman. (k) Are the events causally related; that is, does one of them cause the other? (l) Finally, who wins the bet?

Figure 37-17 shows two clocks in stationary frame S'(they are synchronized in that frame) and one clock in moving frame S. Clocks C1and C'1read zero when they pass each other. When clocks C1and C'2pass each other, (a) which clock has the smaller reading and (b) which clock measures a proper time?

The length of a spaceship is measured to be exactly half its rest length. (a) To three significant figures, what is the speed parameter of the spaceship relative to the observer鈥檚 frame? (b) By what factor do the spaceship鈥檚 clocks run slow relative to clocks in the observer鈥檚 frame?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.