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Assuming that your surface temperature is98.6鈥塅and that you are an ideal blackbody radiator (you are close), find

(a) the wavelength at which your spectral radiancy is maximum,

(b) the power at which you emit thermal radiation in a wavelength range of 1.00nmat that wavelength, from a surface area of4.00鈥塩尘2, and

(c) the corresponding rate at which you emit photons from that area. Using a wavelength of500nm (in the visible range),

(d) recalculate the power and

(e) the rate of photon emission. (As you have noticed, you do not visibly glow in the dark.)

Short Answer

Expert verified

(a) The maximum value of wavelength at which spectral radiancy is maximum is,9.343鈥坝纠

(b) The radiated power is, 1.468105鈥塛.

(c) The rate of emitted photons per second is,6.91014鈥塸丑辞迟辞苍蝉/s .

(d)The radiated power is, 2.221037鈥塛.

(e) The rate of emitted photons per second is, 5.581019鈥塸丑辞迟辞苍蝉/s.

Step by step solution

01

Write the given data from the question.

The surface temperature is,T=98.6鈥塅

The surface area is,A=4鈥塩尘2.

The wavelength range is, =1鈥塶尘.

02

 Step 2: Determine the formulas to calculate wavelength, power and rate of emitting the photons from the surface. 

The expression of Wein鈥檚 displacement law to calculate the wavelength is given as follows.

maxT=2898鈥坝纠.K 鈥(颈)

The expression to calculate the spectral radiancy is given as follows.

S()=2c2h51ehc/kT1 鈥(颈颈)

Here, his the plank鈥檚 constant, cis the speed of light, k is the Boltzmann constant andis the wavelength.

The expression to calculate the radiated power is given as follows.

P=S()A 鈥(颈颈颈)

Here,S()is the spectral radiancy.

The expression to calculate the rate of emitted photons per second is given as follows.

dNdt=Phc 鈥(颈惫)

03

Calculate the wavelength at which spectral radiancy is maximum

(a)

Calculate the temperature from Fahrenheit to kelvin,

T=(98.6鈥塅32)鈥塁59+273.15鈥块T=37鈥塁+273.15鈥块T=310.15鈥块

Calculate the wavelength,

Substitute310.15鈥块 for T into equation (i).

max310.15鈥块=2898鈥坝纠.Kmax=2898鈥坝纠.K310.15鈥块max=9.343鈥坝纠

Hence the maximum value of wavelength at which spectral radiancy is maximum is 9.343鈥坝纠.

04

 Step 4: Calculate the radiated power for the 1 nmwavelength range and 4 cm2surface area.

(b)

Calculate the spectral radiancy.

Substitute 1.381023鈥塉/Kfor K ,6.6210-34mkg/s for h,3108鈥尘/c2 for c, 310.15鈥块for T and9.343鈥坝纠 for into equation (i).

s()=2(3108鈥尘/c2)26.621034鈥尘kg/s(9.343106鈥尘)51e6.621034鈥尘kg/s3108鈥尘/c29.343106鈥尘1.381023鈥塉/K310.15鈥块1s()=374.35211018鈥尘3.kg/s.c47.1191026鈥尘57.00103s()=3.67107鈥塛/m3

Calculate the radiated power.

Substitute3.67107鈥塛/m3 forS(),1鈥塶尘 for and4鈥塩尘2 for A into equation (iii).

P=3.67107鈥塛/m34104鈥尘21109鈥尘P=14.68106鈥塛P=1.468105鈥塛

Hence the radiated power is 1.468105鈥塛.

05

Calculate the rate of emitted photons from the area.

(c)

Calculate the rate of emitted photons.

Substitute 1.468105鈥塛for P ,9.343鈥坝纠 for , 6.6210-34mkg/sfor h, and3108鈥尘/s for into equation (iv).

dNdt=9.343106鈥尘1.468105鈥塛6.621034鈥尘kg/s3108鈥尘/sdNdt=6.91014鈥塸丑辞迟辞苍蝉/s

Hence the rate of emitted photons per second is 6.91014鈥塸丑辞迟辞苍蝉/s.

06

Calculate the radiated power for the wavelength range and surface area.

(d)

The value of the wavelength,=500鈥塶尘

Calculate the spectral radiancy.

Substitute 1.381023鈥塉/Kfor k , 6.6210-34mkg/sfor h , 3108鈥尘/sfor c,310.15鈥块 for T and 500鈥塶尘for into equation (i).

s()=2(3108鈥尘/c2)26.621034鈥尘kg/s(500109鈥尘)51e6.621034鈥尘kg/s3108鈥尘/c2500109鈥尘1.381023鈥塉/K310.15鈥块1s()=374.35211018鈥尘3.kg/s.c43.1251032鈥尘54.651041s()=5.561025鈥塛/m3

Calculate the radiated power.

Substitute5.561025鈥塛/m3 for S(), 1鈥塶尘for and4鈥塩尘2 for A into equation (iii).

P=5.561025鈥塛/m34104鈥尘21109鈥尘P=2.221037鈥塛

Hence the radiated power is2.221037鈥塛

07

Calculate the rate of emitted photons from the area.

(e)

Calculate the rate of emitted photons.

Substitute2.221037鈥塛 for P, 500鈥塶尘for , 6.6210-34mkg/sfor h,and 3108鈥尘/sfor c into equation (iv).

dNdt=500109鈥尘2.221037鈥塛6.621034鈥尘kg/s3108鈥尘/sdNdt=5.581019鈥塸丑辞迟辞苍蝉/s

Hence the rate of emitted photons per second is5.581019鈥塸丑辞迟辞苍蝉/s.

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