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For the thermal radiation from an ideal blackbody radiator with a surface temperature of 2000鈥块, let Icrepresent the intensity per unit wavelength according to the classical expression for the spectral radiancy and Iprepresent the corresponding intensity per unit wavelength according to the Planck expression. What is the ratio Ic/Ipfor a wavelength of

(a) 400鈥塶尘 (at the blue end of the visible spectrum) and

(b) 200鈥坝纠(in the far infrared)?

(c) Does the classical expression agree with the Planck expression in the shorter wavelength range or the longer wavelength range?

Short Answer

Expert verified

(a) The ratio of Ic/Ipfor wavelength400鈥塶尘 is 3.61106.

(b) The ratio ofIc/Ip for wavelength 200鈥坝纠is 1.018.

(c) The classical expression is agree with the Plank鈥檚 expression in the longer wavelength range

Step by step solution

01

Write the given data from the question.

The surface temperature,T=2000鈥块

The intensity per unit wavelength according to classical radiation is Ic.

The intensity per unit wavelength according to plank鈥檚 radiation is Ip.

02

Determine the formulas to calculate the ratio Ic/Ip.

The expression for the intensity according to classical radiation is given as follows.

Ic=2ckT4

Here,cis the speed of light, kis the Boltzmann constant and is the wavelength.

The expression for the intensity according to Plank鈥檚 radiation is given as follows.

Ip=2c2h51ehc/kT1

Here,h is the plank鈥檚 constant.

03

Calculate the ratio for λ=400 nm .

(a)

The value of Boltzmann constant is,1.381023鈥塉/K.

The value of plank鈥檚 constant is,6.6210-34mkg/s.

Calculate the ratio of Ic/Ip.

IcIp=2ckT42c2h51ehc/kT1IcIp=kThc1ehc/kT1IcIp=kThc(ehc/kT1) 鈥(颈)

Substitute1.381023鈥塉/Kfor K , 6.6210-34mkg/sfor , for h , 3108for c ,2000鈥块for T and 400鈥塶尘for into equation (i).

IcIp=400109鈥尘1.381023鈥塉/K2000鈥块6.6210-34mkg/s3108鈥尘/se6.621034mkg/s3108鈥尘/s400109鈥尘1.381023鈥塉/K2000鈥块1IcIp=1104102919.861026e19.861026110410291IcIp=55.58103(e17.9891)IcIp=55.58103(6.491071)

Solve further as,

IcIp=0.055586.49107IcIp=0.361107IcIp=3.61106

Hence the ratio ofIc/Ip for wavelength 400鈥塶尘is 3.61106.

04

Calculate the ratio Ic/Ip for  λ=200 μm.

(b)

Calculate the ratio of Ic/Ip.

Substitute1.381023鈥塉/Kfor K, 6.6210-34mkg/sfor h , 3108for c, 2000鈥块for T and 200鈥坝纠for into equation (i).

IcIp=200106鈥尘1.381023鈥塉/K2000鈥块6.6210-34mkg/s3108鈥尘/se6.621034mkg/s3108鈥尘/s200106鈥尘1.381023鈥塉/K2000鈥块1IcIp=552102619.861026e19.86102655210261IcIp=27.79(e0.03591)IcIp=27.79(1.03661)

Solve further as,

IcIp=27.790.0366IcIp=1.018

Hence the ratio of Ic/Ipfor wavelength 200mis1.018

05

 Step 5: Determine that classical expression agree with Plank’s expression in the longer or shorter wavelength range  

(c)

From the result of the part (b), it is clear that the classical expression is agree with the Plank鈥檚 expression in the longer wavelength range.

Hence the agreement between Icand Ipis at longer wavelength range.

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Most popular questions from this chapter

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