/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q40P What is the maximum kinetic ener... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the maximum kinetic energy of electrons knocked out of a thin copper foil by Compton scattering of an incident beam of 17.5 keV x-rays? Assume the work function is negligible.

Short Answer

Expert verified

The maximum energy of electron is 1.1 keV.

Step by step solution

01

The given data

Compton scattering of an incident beam of 17.5 keV x-rays is done to knock electrons out a thin copper foil

02

Formula used

Here, Eλ=hc

Where E is energy

λis wavelength

h is Plank’s constant

C is speed of light.

03

Change in the wavelength

Using hc=1240 e³Õâ‹…nm

Eλ=hcλ=hcEλ=1240 e³Õâ‹…nm17500 e³Õ=0.07086 n³¾

Maximum Crompton shift occur forφ=180° yields

Δλ=hcmec2(1−cos180°)=1240 e³Õâ‹…nm511×103 e³Õ1−(−1)=0.00485 n³¾

04

New photon energy

New photon wavelengthλ' is

λ'=0.07086 n³¾+0.00485 n³¾=0.0757 n³¾

E'=hcλ'=1240 e³Õâ‹…nm0.0757 n³¾=1.64×104 e³Õ

New photon energy 16.4 k±ð³Õ

05

Kinetic energy of electron

Kinetic energy of electron is

E'−E=17.5 k±ð³Õ−16.4 k±ð³Õ =1.1 k±ð³Õ

Hence, maximum kinetic energy of electron is 1.1 k±ð³Õ

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.