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An electron, trapped in a one-dimensional infinite potential well 250 pm wide, is in its ground state. How much energy must it absorb if it is to jump up to the state with n=4?

Short Answer

Expert verified

90.3 eV

Step by step solution

01

Given data

The width of the potential well is

L=250pm=0.250nmn=4

02

Energy in a potential well

The nth state energy of a particle of mass in an infinite potential well of width L is

En=n2h28mL..........1

03

Determining the energy required to jump from ground state to the fourth state

Here h is the Planck's constant having value

h=6.626×10-34J.sandc=2.998×108m/shc=6.626×10-34J.s2.998×108m/s1.602×10-19J/eV10-9m/nm=1240eV.nm

Using the value for an electron from Table 37-3 511×103eV, Eq.39 – 4 can be rewritten as

En=n2h28mL2=n2hc28mc2L2

The absorbed energy is

∆E=E4-E1=42-12hc28mec2L2=151240eV.nm28511×103eV0.250nm2=90.3eV

Hence, the required energy is 90.3eV

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Most popular questions from this chapter

A proton and an electron are trapped in identical one-dimensional infinite potential wells; each particle is in its ground state. At the center of the wells, is the probability density for the proton greater than, less than, or equal to that of the electron?

figure 39-28 shows the energy-level diagram for a finite, one-dimensional energy well that contains an electron. The nonquantized region begins at E4=450.0eV. Figure 39-28b gives the absorption spectrum of the electron when it is in the ground state—it can absorb at the indicated wavelengths: λa=14.588nmandλb=4.8437and for any wavelength less than λc=2.9108nm . What is the energy of the first excited state?

The wave functions for the three states with the dot plots shown in Fig. 39-23, which have n = 2 , l = 1 , and 0, and ml=0,+1,-1, are

Ψ210(r,θ)=(1/42Ï€)(a-3/2)(r/a)r-r/2acosθΨ21+1(r,θ)=(1/8Ï€)(a-3/2)(r/a)r-r/2a(²õ¾±²Ôθ)e+¾±Ï•Ψ21-1(r,θ)=(1/8Ï€)(a-3/2)(r/a)r-r/2a(²õ¾±²Ôθ)e-¾±Ï•

in which the subscripts on Ψ(r,θ) give the values of the quantum numbers n , l , and ml the angles θand ϕ are defined in Fig. 39-22. Note that the first wave function is real but the others, which involve the imaginary number i, are complex. Find the radial probability density P(r) for (a)Ψ210 and (b)Ψ21+1 (same as for Ψ21-1 ). (c) Show that each P(r) is consistent with the corresponding dot plot in Fig. 39-23. (d) Add the radial probability densities for Ψ210 , Ψ21+1 , andΨ21-1 and then show that the sum is spherically symmetric, depending only on r.

A hydrogen atom in a state having a binding energy (the energy required to remove an electron) of 0.85 eV makes a transition to a state with an excitation energy (the difference between the energy of the state and that of the ground state) of 10.2eV. (a) What is the energy of the photon emitted as a result of the transition? What are the (b) higher quantum number and (c) lower quantum number of the transition producing this emission?

An electron in the n = 2 state in the finite potential well of Fig. 39-7 absorbs 400 eV of energy from an external source. Using the energy-level diagram of Fig. 39-9, determine the electron’s kinetic energy after this absorption, assuming that the electron moves to a position for which x > L.

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