91Ó°ÊÓ

$\mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{Chaldron}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{Bag}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{Pottle}\mathbf{=}\mathbf{120240}$

The volume of 1 bag${}^{\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{1091}\mathbf{}{\mathbf{m}}^{\mathbf{3}}}$

Unit conversion is the conversion between different units of measure for the same quantity, usually through multiplier conversion factors.

Use the relationship between wey and chaldron to calculate the first value in first column.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{wey}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{Chaldron} \\ \frac{\mathbf{1}\mathbf{×}\mathbf{9}}{\mathbf{10}}\mathbf{wey}\mathbf{=}\mathbf{1}\mathbf{}\mathbf{Chaldron} \\ \mathbf{1}\mathbf{}\mathbf{Chaldron}\mathbf{=}\frac{\mathbf{9}}{\mathbf{10}}\mathbf{}\mathbf{wey}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{900}\mathbf{}\mathbf{way}\mathbf{} \end{gathered}$$

Use the relationship between wey and bag to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{wey}\mathbf{=}\frac{40}{3}\mathit{b}\mathit{a}\mathit{g} \\ \frac{\mathbf{1}\mathbf{×}\mathbf{3}}{\mathbf{40}}\mathbf{wey}\mathbf{=}\mathbf{1}\mathbf{}\mathit{b}\mathit{a}\mathit{g} \\ \mathbf{1}\mathbf{}\mathit{b}\mathit{a}\mathit{g}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{50}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{}\mathbf{wey} \end{gathered}$$

Thus, ${}^{\mathbf{1}\mathbf{}\mathbf{bag}}$is equal to ${}^{\mathbf{7}\mathbf{.}\mathbf{50}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{}\mathbf{wey}}$

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{1}\mathbf{}\mathbf{pottle}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{56}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}\mathbf{}}\mathbf{way}\mathbf{} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{pottle}}$is equal to ${}^{\mathbf{1}\mathbf{.}\mathbf{56}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}\mathbf{}}\mathbf{way}\mathbf{}}$.

Use the relationship between wey and pottle to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{1}\mathbf{}\mathbf{gill}\mathbf{=}\mathbf{8}\mathbf{.}\mathbf{32}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{6}\mathbf{}}\mathbf{way}\mathbf{} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{gill}}$is equal tolocalid="1654605291666" ${}^{\mathbf{8}\mathbf{.}\mathbf{32}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{6}\mathbf{}}\mathbf{way}\mathbf{}}$.

As the conversion is from chaldron to chaldron, it will be 1.00.

Use the relationship between bag and chaldron to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{Bag} \end{gathered}$$

Therefore,

$$\begin{gathered} \frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{Bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{bag}\mathbf{=}\frac{\mathbf{10}\mathbf{×}\mathbf{3}}{\mathbf{9}\mathbf{×}\mathbf{40}}\mathbf{Chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{8}\mathbf{.}\mathbf{33}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{Chaldron} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{bag}}$is equal to${}^{\mathbf{8}\mathbf{.}\mathbf{33}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{Chaldron}}$.

Use the relationship between pottle and chaldron to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \end{gathered}$$

Therefore,

localid="1654604729304" $$\begin{gathered} \frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron}\mathbf{}\mathbf{=}\mathbf{}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{pottle}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}\mathbf{×}\mathbf{640}}\mathbf{}\mathbf{chaldron}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{}\mathbf{1}\mathbf{.}\mathbf{74}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\mathbf{chaldron} \end{gathered}$$

Use the relationship between gill and chaldron to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \end{gathered}$$

Therefore

localid="1654605089506" $$\begin{gathered} \frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron}\mathbf{}\mathbf{=}\mathbf{}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{gill}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}\mathbf{×}\mathbf{120240}}\mathbf{}\mathbf{chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{9}\mathbf{.}\mathbf{24}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{6}}\mathbf{}\mathbf{chaldron} \end{gathered}$$

Thus, ${}^{\mathbf{1}\mathbf{}\mathbf{gill}}$is equal to localid="1654605354518" ${}^{\mathbf{9}\mathbf{.}\mathbf{24}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{6}}\mathbf{}\mathbf{chaldron}}$.

Use the relationship between chaldron and bag to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{Bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{} \end{gathered}$$

Therefore,

$$\begin{gathered} \frac{\mathbf{40}}{\mathbf{3}}\mathbf{Bag}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{chaldron} \\ \mathbf{1}\mathbf{}\mathbf{chaldron}\mathbf{=}\frac{\mathbf{40}\mathbf{×}\mathbf{9}}{\mathbf{3}\mathbf{×}\mathbf{10}}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{12}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{chaldron}}$is equal to${}^{\mathbf{12}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{bag}}$.

As the conversion is from bag to bag, the next value will be 1.00

To calculate the next value, use the relationship between pottle and bag.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \end{gathered}$$

Therefore,

$$\begin{gathered} \frac{\mathbf{40}}{\mathbf{3}}\mathbf{}\mathbf{bag}\mathbf{}\mathbf{=}\mathbf{}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{pottle}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}\mathbf{×}\mathbf{640}}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{08}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{bag} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{pottle}}$is equal to ${}^{\mathbf{2}\mathbf{.}\mathbf{08}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{2}}\mathbf{}\mathbf{bag}}$.

Use the relationship between gill and bag, to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \end{gathered}$$

Therefore,

$$\begin{gathered} \frac{\mathbf{40}}{\mathbf{3}}\mathbf{}\mathbf{bag}\mathbf{}\mathbf{=}\mathbf{}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{gill}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}\mathbf{×}\mathbf{120240}}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{11}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{4}}\mathbf{}\mathbf{bag} \end{gathered}$$

To calculate the next value, use the relation between chaldron and pottle.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{chaldron} \end{gathered}$$

Then,

$$\begin{gathered} \mathbf{640}\mathbf{}\mathbf{pottle}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{chaldron} \\ \mathbf{1}\mathbf{}\mathbf{chaldron}\mathbf{=}\frac{\mathbf{640}\mathbf{×}\mathbf{9}}{\mathbf{10}}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{576}\mathbf{}\mathbf{pottle} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{chaldron}}$is equal to ${}^{\mathbf{576}\mathbf{}\mathbf{pottle}}$.

Use the relation between bag and pottle to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{bag} \end{gathered}$$

Then,

role="math" localid="1654607184405" $$\begin{gathered} \mathbf{640}\mathbf{}\mathbf{pottle}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{bag}\mathbf{=}\frac{\mathbf{640}\mathbf{×}\mathbf{3}}{\mathbf{40}}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{48}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{pottle} \end{gathered}$$

${}^{\mathbf{48}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{pottle}}$.Thus, ${}^{\mathbf{1}\mathbf{}\mathbf{bag}}$is equal to

As the conversion is from pottle to pottle, it will be 1.00.

To calculate the next value, use the relation between gill and pottle.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \end{gathered}$$

Then,

$$\begin{gathered} \mathbf{640}\mathbf{}\mathbf{pottle}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{}\mathbf{gill}\mathbf{=}\frac{\mathbf{640}}{\mathbf{120240}}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{5}\mathbf{.}\mathbf{32}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\mathbf{}\mathbf{pottle} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{gill}}$is equal to ${}^{\mathbf{5}\mathbf{.}\mathbf{32}\mathbf{×}{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\mathbf{}\mathbf{pottle}}$.

Use the relation between chaldron and gill to find the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{childron} \end{gathered}$$

Then,

$$\begin{gathered} \mathbf{120240}\mathbf{}\mathbf{gill}\mathbf{}\mathbf{=}\frac{\mathbf{10}}{\mathbf{9}}\mathbf{}\mathbf{childron} \\ \mathbf{1}\mathbf{}\mathbf{chaldron}\mathbf{=}\frac{\mathbf{120240}\mathbf{×}\mathbf{9}}{\mathbf{10}}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{08}\mathbf{×}{\mathbf{10}}^{\mathbf{5}}\mathbf{}\mathbf{gill}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{childron}}$is equal to ${}^{\mathbf{1}\mathbf{.}\mathbf{08}\mathbf{×}{\mathbf{10}}^{\mathbf{5}}\mathbf{}\mathbf{gill}}$

Use the relationship between bag and gill to find the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{40}}{\mathbf{3}}\mathbf{}\mathbf{bag} \end{gathered}$$

Then,

$$\begin{gathered} \mathbf{1}\mathbf{}\mathit{b}\mathit{a}\mathit{g}\mathbf{=}\frac{\mathbf{120240}\mathbf{×}\mathbf{3}}{40}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{9}\mathbf{.}\mathbf{02}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{bag}}$is equal to ${}^{\mathbf{9}\mathbf{.}\mathbf{02}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}\mathbf{gill}}$.

Use the relation between pottle and gill to calculate the next value.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{way}\mathbf{}\mathbf{=}\mathbf{120240}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \end{gathered}$$

Then,

$$\begin{gathered} \mathbf{120240}\mathbf{}\mathbf{gill}\mathbf{=}\mathbf{640}\mathbf{}\mathbf{pottle} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{1}\mathbf{pottle}\mathbf{}\mathbf{=}\frac{\mathbf{120240}}{\mathbf{640}}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{187}\mathbf{.}\mathbf{87}\mathbf{}\mathbf{gill} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{188}\mathbf{}\mathbf{gill} \end{gathered}$$

Therefore, ${}^{\mathbf{1}\mathbf{}\mathbf{pottle}}$is equal to ${}^{\mathbf{188}\mathbf{}\mathbf{gill}}$.

As the conversion is from gill to gill, it will be 1.00.

It is given that,

$\mathbf{1}\mathbf{}\mathbf{bag}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{1091}\mathbf{}{\mathbf{m}}^{\mathbf{3}}$

from part (c), ${}^{\mathbf{1}\mathbf{}\mathbf{chaldron}\mathbf{=}\mathbf{12}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{bag}}$

Therefore,

$$\begin{gathered} \mathbf{1}\mathbf{.}\mathbf{5}\mathbf{}\mathbf{chaldron}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{5}\mathbf{×}\mathbf{12}\mathbf{.}\mathbf{0}\mathbf{}\mathbf{bag} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{18}\mathbf{}\mathbf{bag} \end{gathered}$$

Each bag is ${}^{\mathbf{0}\mathbf{.}\mathbf{1091}\mathbf{}{\mathbf{m}}^{\mathbf{3}}}$

$$\begin{gathered} \mathbf{1}\mathbf{.}\mathbf{5}\mathbf{}\mathbf{childron}\mathbf{=}\mathbf{18}\mathbf{×}\mathbf{0}\mathbf{.}\mathbf{1091}\mathbf{}{\mathbf{m}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{196}\mathbf{}{\mathbf{m}}^{\mathbf{3}} \end{gathered}$$

Therefore, the volume of ${}^{\mathbf{1}\mathbf{.}\mathbf{5}\mathbf{}\mathbf{chaldron}}$ is ${}^{\mathbf{1}\mathbf{.}\mathbf{96}\mathbf{}{\mathbf{m}}^{\mathbf{3}}}$.