91Ó°ÊÓ

$\mathbf{1}\mathbf{}\mathbf{apple}\mathbf{}\mathbf{barrel}\mathbf{=}\mathbf{7056}\mathbf{}{\mathbf{inch}}^{\mathbf{3}}$

Unit conversion is the conversion between different units of measure for the same quantity, usually through multiplier conversion factors. Here, apple barrel and cranberry are the different units for the quantity volume.

Assume that the total volume in the cranberry barrel is ${}^{{\mathbf{V}}_{\mathbf{c}}}$and the total volume in the apple barrel is ${}^{{\mathbf{V}}_{\mathbf{A}}}$.

The total volume in the cranberry barrel is calculated as:

$$\begin{gathered} {\mathbf{V}}_{\mathbf{c}}\mathbf{=}\mathbf{20}\mathbf{×}\mathbf{}\mathbf{Volume}\mathbf{}\mathbf{of}\mathbf{}\mathbf{cranberry}\mathbf{}\mathbf{barrel} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{20}\mathbf{×}\mathbf{5826}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{11652}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{116}\mathbf{.}\mathbf{52}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{} \end{gathered}$$

Therefore, the total volume of the cranberry barrel is${}^{\mathbf{116}\mathbf{.}\mathbf{52}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}}}$

The total volume in the apple barrel is calculated as:

$$\begin{gathered} {\mathbf{V}}_{\mathbf{A}}\mathbf{=}\mathbf{20}\mathbf{×}\mathbf{×}\mathbf{Volume}\mathbf{}\mathbf{of}\mathbf{}\mathbf{apple}\mathbf{}\mathbf{barrel} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{20}\mathbf{×}\mathbf{7056}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{141120}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{141}\mathbf{.}\mathbf{12}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \end{gathered}$$

Therefore, the total volume of the apple barrel islocalid="1654325275805" ${}^{\mathbf{141}\mathbf{.}\mathbf{12}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}}}$.

The discrepancy in the shipment volume received by the customer ${}^{(∆V)}$is equal to the difference in the volumes of cranberry barrel and apple barrel. Therefore,

$$\begin{gathered} \mathbf{Δ³Õ}\mathbf{=}{\mathbf{V}}_{\mathbf{A}}\mathbf{-}{\mathbf{V}}_{\mathbf{C}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{141}\mathbf{.}\mathbf{12}\mathbf{×}{\mathbf{10}}^{\mathbf{3}\mathbf{}}{\mathbf{inch}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{24}\mathbf{.}\mathbf{6}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}} \end{gathered}$$

The discrepancy in volume in liters is,

$$\begin{gathered} \mathbf{Δ³Õ}\mathbf{=}\mathbf{24}\mathbf{.}\mathbf{6}\mathbf{×}{\mathbf{10}}^{\mathbf{3}}\mathbf{}{\mathbf{inch}}^{\mathbf{3}\mathbf{×}}\mathbf{}\frac{\mathbf{1}\mathbf{}\mathbf{liter}}{\mathbf{61}\mathbf{.}\mathbf{0237}\mathbf{}{\mathbf{inch}}^{\mathbf{3}}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{403}\mathbf{.}\mathbf{122}\mathbf{}\mathbf{liters} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{≈}\mathbf{403}\mathbf{}\mathbf{liters} \end{gathered}$$

Thus, the discrepancy in the shipment volume is ${}^{\mathbf{403}\mathbf{}\mathbf{liters}}$.