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A boy is initially seated on the top of a hemispherical ice mound of radiusR = 13.8 m. He begins to slide down the ice, with a negligible initial speed (Figure). Approximate the ice as being frictionless. At what height does the boy lose contact with the ice?

Short Answer

Expert verified

The height at which the boy lose contact with the ice is h = 9.20 m.

Step by step solution

01

Step 1: Given

The radius of the hemispherical ice mound is R = 0.138 m .

02

Determining the concept

Use the concept of the energy conservation law and gravitational potential energy of the boy. According to the law of energy conservation, energy can neither be created, nor be destroyed.

Formulae:

U=mghK=12mv2

Where,

K is kinetic energy, Uis potential energy, m is mass, v is velocity, g is an acceleration due to gravity and h is height.

03

Determining theheight at which the boy lose contact with the ice


Consider,FNis the normal force acting on the boy in the upward direction as shown in the free body diagram. The acceleration of the boy at that point is centripetal acceleration,

a=v22

According to the Newton鈥檚 second law,

Fnet=mamgcos-FN=mv22

The boy leaves the ice at the pointFN=0, then,

mgcos=mv22gcos=v22

(i)

The gravitational potential energy of the at the point where he leaves the mound is,

U=-mgR1-cos

The body starts from the rest. The kinetic energy at that point is,

K=12mv2

According to the energy conservation law,

0=12mv2-mgR1-cos12mv2=mgR1-cos12v2=gR1-cosv2=2gR1-cosEquationibecomessas,gcos=2gR1-cosRcos=21-coscos=2-2cos3cos=2cos=23

The height of the boy above the bottom of the mound is,

h=Rcosh=13.8mx23h=9.20m

Hence, the height at which the boy lose contact with the ice is h = 9.20 m

Therefore, the height of the boy at the point where he leaves the mound can be found by using the concept of conservation of energy and the gravitational potential energy.

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