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A forceFais applied to a bead as the bead is moved along a straight wire through displacement+5.0cm. The magnitude ofrole="math" localid="1657167569087" Fais set at a certain value, but theangleFabetween and the bead鈥檚 displacement can be chosen. Figure7-45gives the workWdone byon the bead for a range of role="math" localid="1657166842505" values;role="math" localid="1657167794268" W0=25J. How much work is done byrole="math" localid="1657167547441" Faif is (a) 64and (b)147?

Short Answer

Expert verified
  1. Work done when =64is 11J.
  2. Work done when =147is -21J.

Step by step solution

01

Given information

It is given that, graph of work done with various values of,

W0=25J,when=0,x=5.0cm=0.05m.

02

Determining the concept

The problem deals with the power and the work done. Work, energy, and power are the fundamental concepts of physics. Work is the displacement of an object when force is applied on it.By using the value ofW0find the applied force Fa, which can be used to find the work done 64cat and147.

Formula:

W=Fdcos

where,F is force, dis displacement and Wis the work done

03

(a) determining the work done when φ=64°

From the graph,

W0=25JW0=Fa.xFa=250.05Fa=500N

Hence, work done when =64is 11J.

04

(b) determining the work done when ϕ=147°.

Work done when =64,

W=Facos64W=5000.050.4383W=10.9575JW11JW=Facos147W=5000.05(-0.8386)W=-20.96JW=-20.96JW-21J

Hence, work done when =147is-21J.

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