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$$\begin{gathered} 1\mathrm{displacement}\mathrm{ton}=7\mathrm{barrel}\mathrm{bulk} \\ 1\mathrm{freight}\mathrm{ton}=8\mathrm{barrel}\mathrm{bulk} \\ 1\mathrm{register}\mathrm{ton}=20\mathrm{barrel}\mathrm{bulk} \end{gathered}$$

Unit conversion is the conversion between different units of measure for the same quantity, usually through multiplier conversion factors. Here, displacement ton, freight ton, register ton and barrel bulk and bushels are the different units for the quantity volume.

To calculate the number of extra U.S. bushels, you must first convert all the tons into their equivalent U.S. bushels.

$$\begin{gathered} \mathbf{1}\mathbf{}{\mathbf{m}}^{\mathbf{3}}\mathbf{=}\mathbf{28}\mathbf{.}\mathbf{378}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushels} \\ \mathbf{1}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}\mathbf{=}\mathbf{}\mathbf{0}\mathbf{.}\mathbf{1415}\mathbf{}{\mathbf{m}}^{\mathbf{3}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{1415}\mathbf{}{\mathbf{m}}^{\mathbf{3}}\mathbf{脳}\frac{\mathbf{28}\mathbf{.}\mathbf{378}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushel}}{\mathbf{1}\mathbf{}{\mathbf{m}}^{\mathbf{3}}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{4}\mathbf{.}\mathbf{0155}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushel} \end{gathered}$$

Therefore, $\mathbf{1}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}$is equivalent to $\mathbf{4}\mathbf{.}\mathbf{0155}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushel}$.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{displacement}\mathbf{}\mathbf{ton}\mathbf{}\mathbf{=}\mathbf{}\mathbf{7}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{}\mathbf{7}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}\mathbf{脳}\frac{\mathbf{4}\mathbf{.}\mathbf{0155}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushels}}{\mathbf{1}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{28}\mathbf{.}\mathbf{108}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushel}\mathbf{} \end{gathered}$$

Therefore, $\mathbf{1}\mathbf{}\mathbf{displacement}\mathbf{}\mathbf{ton}$ is equivalent to $\mathbf{28}\mathbf{.}\mathbf{108}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushel}\mathbf{}$.

Now, use the relationship between freight ton and barrels bulk to find the relationship between freight ton and U.S. bushels.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathit{f}\mathit{r}\mathit{e}\mathit{i}\mathit{g}\mathit{h}\mathit{t}\mathbf{}\mathit{t}\mathit{o}\mathit{n}\mathbf{}\mathbf{=}\mathbf{}\mathbf{8}\mathbf{}\mathit{b}\mathit{a}\mathit{r}\mathit{r}\mathit{e}\mathit{l}\mathbf{}\mathit{b}\mathit{u}\mathit{l}\mathit{k}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{}\mathbf{8}\mathbf{}\mathit{b}\mathit{a}\mathit{r}\mathit{r}\mathit{e}\mathit{l}\mathit{s}\mathbf{}\mathit{b}\mathit{u}\mathit{l}\mathit{k}\mathbf{}\mathbf{脳}\frac{\mathbf{4}\mathbf{.}\mathbf{0155}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{b}\mathbf{u}\mathbf{s}\mathbf{h}\mathbf{e}\mathbf{l}\mathbf{s}}{\mathbf{1}\mathbf{}\mathbf{b}\mathbf{a}\mathbf{r}\mathbf{r}\mathbf{e}\mathbf{l}\mathbf{}\mathbf{b}\mathbf{u}\mathbf{l}\mathbf{k}\mathbf{}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{32}\mathbf{.}\mathbf{124}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathit{b}\mathit{u}\mathit{s}\mathit{h}\mathit{e}\mathit{l}\mathit{s}\mathbf{} \end{gathered}$$

Therefore, $\mathbf{1}\mathbf{}\mathbf{freight}\mathbf{}\mathbf{ton}\mathbf{}$is equivalent to $\mathbf{32}\mathbf{.}\mathbf{124}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushels}\mathbf{}$.

Now, use the relationship between register ton and barrels bulk to find the relationship between register ton and U.S. bushels.

$$\begin{gathered} \mathbf{1}\mathbf{}\mathbf{register}\mathbf{}\mathbf{ton}\mathbf{}\mathbf{=}\mathbf{20}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{20}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}\mathbf{脳}\frac{\mathbf{4}\mathbf{.}\mathbf{0155}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{}\mathbf{bushels}\mathbf{}}{\mathbf{1}\mathbf{}\mathbf{barrel}\mathbf{}\mathbf{bulk}\mathbf{}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{80}\mathbf{.}\mathbf{31}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushels}\mathbf{} \end{gathered}$$

Therefore, $\mathbf{1}\mathbf{}\mathbf{register}\mathbf{}\mathbf{ton}\mathbf{}$ is equivalent to $\mathbf{80}\mathbf{.}\mathbf{31}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushels}\mathbf{}$
.

The extra U.S. bushels can be given as:

$\mathbf{Extra}\mathbf{}\mathbf{bushels}\mathbf{}\mathbf{=}\mathbf{}\mathbf{73}\mathbf{}\mathbf{脳}\left(\mathrm{freight}\mathrm{tons}-\mathrm{displacement}\mathrm{tons}\right)$.

Substitute the values in the above expression.

$$\begin{gathered} \mathbf{Extra}\mathbf{}\mathbf{bushels}\mathbf{}\mathbf{=}\mathbf{}\mathbf{73}\mathbf{脳}\left(32.124U.S.\mathrm{bushels}-28.108U.S.\mathrm{bushels}\right) \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{293}\mathbf{.}\mathbf{168}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushles} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{鈮�}\mathbf{293}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushles} \end{gathered}$$

Thus, when the order is interpreted as 73 freight tons, the extra U.S. bushels are 293 U.S. bushels.

The extra U.S. bushels can be given as:

$\mathbf{Extra}\mathbf{}\mathbf{bushels}\mathbf{}\mathbf{=}\mathbf{}\mathbf{73}\mathbf{}\mathbf{脳}\left(\mathrm{freight}\mathrm{tons}-\mathrm{displacement}\mathrm{tons}\right)$

Substitute the values in the above expression.

$$\begin{gathered} \mathbf{Extra}\mathbf{}\mathbf{bushels}\mathbf{}\mathbf{=}\mathbf{}\mathbf{73}\mathbf{脳}\mathbf{(}\mathbf{80}\mathbf{.}\mathbf{31}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushels}\mathbf{}\mathbf{-}\mathbf{}\mathbf{28}\mathbf{.}\mathbf{108}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushels}\mathbf{)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{3810}\mathbf{.}\mathbf{74}\mathbf{}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushles} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{鈮�}\mathbf{3}\mathbf{.}\mathbf{81}\mathbf{脳}{\mathbf{10}}^{\mathbf{3}}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushles} \end{gathered}$$

Thus, when the order is interpreted as 73 register tons, the extra U.S. bushels are $\mathbf{3}\mathbf{.}\mathbf{81}\mathbf{脳}{\mathbf{10}}^{\mathbf{3}}\mathbf{U}\mathbf{.}\mathbf{S}\mathbf{.}\mathbf{}\mathbf{bushles}$.