/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q8Q Figure 32-24 shows three loop mo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Figure 32-24 shows three loop models of an electron orbiting counterclockwise within a magnetic field. The fields are non-uniform for models 1 and 2 and uniform for model 3. For each model, are (a) the magnetic dipole moment of the loop and (b) the magnetic force on the loop directed up, directed down, or zero?

Short Answer

Expert verified
  1. The magnetic dipole moment of the loop for all the models will be downward perpendicular to the plane of the circular loop.
  2. The magnetic force on the loop for models 1 and 2 is zero and model three is directed up.

Step by step solution

01

Given data

Figure 32-24 with three loop models of an electron orbiting counter-clockwise within a given magnetic field is given.

02

Understanding the concept of direction of the magnetic dipole moment and the force

The concept of magnetic dipole moment defines the amount of the current flowing through a given area. Using the Fleming’s left-hand thumb rule, when we curl the fingers of our hand in the direction of the effective current, then the thumb indicates the direction of the dipole moment.

The magnetic force gives the amount of attraction or repulsion that arises between the charged particles due to their motion. The direction of this force is given by using the right-hand rule for a negative charge as the given particle is an electron.

Formulae:

The magnetic dipole moment of a particle, μ=iA..........1

The magnetic force of a particle, F⇶Ä=qv⇶Ä×B⇶ÄorF=qvBsinθ

where, θ is the magnetic field, q is the charge, v is the particle velocity, and θis the angle between particle velocity and magnetic field.

03

a) Calculation of the magnetic dipole moment for all the given models

As the direction of magnetic dipole moment depends on planar area of the current loop considering equation (1), thus, the direction of the moment is only given by the direction of motion of the effective current using thumb rule.

Here, the electron is in counterclockwise direction. Thus, the effective current will be opposite of electron’s direction that is clockwise. Now, using right-hand thumb rule, the direction of the magnetic file will be downward perpendicular to the plane of the circular loop for all the three given models.

04

b) Calculation of the direction of the magnetic force

For model 1 and model 2,

Here, the magnetic field is non-uniform and is directed downward to the plane with increasing intensity for both the models. Thus, every dipole present there is an equal and opposite force directed and thus they cancel each other resulting in a zero.

For model 3,

As the magnetic field is uniform and the electron is moving counter clockwise that is perpendicular to the field direction, considering equation (1), it can be said that the force on it is direction inward and perpendicular to both the particle and magnetic field direction.

Hence, the force is zero for model 1 and 2 while is directed upward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A charge q is distributed uniformly around a thin ring of radiusr . The ring is rotating about an axis through its center and perpendicular to its plane, at an angular speedӬ. (a) Show that the magnetic moment due to the rotating charge has magnitude μ=12qӬr2. (b) What is the direction of this magnetic moment if the charge is positive?

Figure 32-20 shows a parallel-plate capacitor and the current in the connecting wires that are discharging the capacitor. Are the directions of (a) electric field E⇶Äand (b) displacement current idleftward or rightward between the plates? (c) Is the magnetic field at point P into or out of the page?

In Fig. 32-36, a capacitor with circular plates of radius R=18.0cmis connected to a source of emf ξ=ξmsinÓ¬t, where ξm=220Vand Ó¬=130rad/s. The maximum value of the displacement current is id=7.60μA . Neglect fringing of the electric field at the edges of the plates. (a) What is the maximum value of the currenti in the circuit? (b) What is the maximum value ofdÏ•E/dt , whereÏ•E is the electric flux through the region between the plates? (c) What is the separation dbetween the plates? (d) Find the maximum value of the magnitude of Bâ‡¶Ä between the plates at a distancer=11.0cmfrom the center.

A capacitor with square plates of edge length L is being discharged by a current of 0.75 A. Figure 32-29 is a head-on view of one of the plates from inside the capacitor. A dashed rectangular path is shown. If L = 12cm, W = 4.0 cm , and H = 2.0 cm , what is the value ∮B⇶Ä×ds⇶Äof around the dashed path?

Figure 32-27 shows a closed surface. Along the flat top face, which has a radius of 2.0 cm, a perpendicular magnetic field B⇶Äof magnitude 0.30 T is directed outward. Along the flat bottom face, a magnetic flux 0.70 mWb is directed outward. What are the (a) magnitude and (b) direction (inward or outward) of the magnetic flux through the curved part of the surface?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.