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A particular type of fundamental particle decays by transforming into an electron e−and a positron e+. Suppose the decaying particle is at rest in a uniform magnetic field of magnitude3.53mT and the e− and e+move away from the decay point in paths lying in a plane perpendicular to B→ . How long after the decay do the e− and e+collide?

Short Answer

Expert verified

e−and e+ will collide after 5.05×10−9 s following the decay.

Step by step solution

01

Listing the given quantities

Magnetic field B=3.53 mT=3.53×10−3 T.

02

Understanding the concept of the period of motion

We need to use the formula of the period of motion of charged particle into a magnetic field to find the period of the particle. As each particle travels only a half-circular path, dividing this period by 2, we will get the required time after which andwill collide.

Formula:

T=2Ï€me/qB

03

Calculation of theafter the decay when  e-and e+  collide

We have:

T=2Ï€meqB=2Ï€(9.1×10−31 k²µ)(1.6×10−19 C)(3.53×10−3â€Í¿)=1.01×10−8 s

But, each particle travels only a half-circular path. So,

t=T2=1.01×10−8 s2=5.05×10−9 s

Therefore, 5.05×10−9 safter of the decay, e−and e+will collide.

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