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A solenoid that is 95.0cmlong has a radius of2.00cmand a winding ofrole="math" localid="1663136568607" 1200turns; it carries a current of3.60A. Calculate the magnitude of the magnetic field inside the solenoid.

Short Answer

Expert verified

The magnitude of the magnetic field inside the solenoid is 0.00571T.

Step by step solution

01

Listing the given quantities

l=95cm=0.95m

N=1200

i=3.60A

02

Understanding the concept of magnetic field and toroid 

The magnetic field produced by the solenoid is given as,

B=μ0in=μ0i(Nl)

Here, B is the magnetic field, i is current, n is the number of turns per unit length, N is the total number of turns and l is the length of the solenoid.

We can calculate the magnetic field due to an ideal solenoid. In our case, the solenoid is having a definite length, so we use this equation to calculate the magnetic field inside the solenoid.

03

Calculating the magnetic field inside the solenoid.

By using the equation,we can calculate the magnetic field.

B=μ0in=μ0iNl=1.26×10−6×3.60×12000.95=0.00571T

Therefore, the magnitude of the magnetic field inside the solenoid is 0.00571T.

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