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Chapter 29: Q51P (page 836)

A 200鈭�turnsolenoid having a length of25cmand a diameter of10cmcarries a current of0.29A. Calculate the magnitude of the magnetic field inside the solenoid.

Short Answer

Expert verified

The magnitude of the magnetic field inside the solenoid is 3脳10-4T.

Step by step solution

01

Listing the given quantities

  • l=25鈥�cm=0.25m
  • d=10鈥�cm=0.10m
  • N=200
  • i=0.29A
02

Understanding the concept of magnetic field and solenoid  

We can calculate the magnetic field due to an ideal solenoid. In our case, the solenoid has a definite length, so we use this equation to calculate the magnetic field inside the solenoid.

Formula:

B=渭0in=渭0iNl

03

Calculate the magnitude of the magnetic field

We can calculate the magnetic field.

B=渭0in=渭0iNl=1.26脳10-6脳0.29脳2000.25=2.92脳10-4T鈮�3脳10-4T

Hence, the magnitude of the magnetic field inside the solenoid is 3脳10-4T.

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Most popular questions from this chapter

Each of the eight conductors in Figure carries 2.0Aof current into or out of the page. Two paths are indicated for the line integral. 鈭�B鈫�.ds鈫�(a) What is the value of the integral for path 1 and (b) What is the value of the integral for path 2?

Figure 29-80 shows a cross-section of a long cylindrical conductor of radius a=4鈥�cmcontaining a long cylindrical hole of radiusb=1.50cm. The central axes of the cylinder and hole are parallel and are distanced=2cmapart; currentis uniformly distributed over the tinted area. (a) What is the magnitude of the magnetic field at the center of the hole? (b) Discuss the two special casesb=0andd=0.

Question:In Figure, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a=20cm. The currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3, and each wire carries 20 A. In unit-vector notation, what is the net magnetic field at the square鈥檚 center?

Figure 29-88 shows a cross section of a long conducting coaxial cable and gives its radii (a,b,c). Equal but opposite currents iare uniformly distributed in the two conductors. Derive expressions for B (r) with radial distance rin the ranges (a) r < c, (b) c< r <b , (c) b < r < a, and (d) r > a . (e) Test these expressions for all the special cases that occur to you. (f) Assume that a = 2.0 cm, b = 1.8 cm, c = 0.40 cm, and i = 120 A and plot the function B (r) over the range 0 < r < 3 cm .

A straight conductor carrying current i=5.0Asplits into identical semicircular arcs as shown in Figure. What is the magnetic field at the center C of the resulting circular loop?
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