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Chapter 29: Q74P (page 862)

The magnitude of the magnetic field 88.0cmfrom the axis of a long straight wire is7.30渭罢. What is the current in the wire?

Short Answer

Expert verified

The current in the wire is 32.1A.

Step by step solution

01

Given Data

  1. Distance R=88cm=0.88m
  2. The magnitude of magnetic field B=7.30渭罢
02

Understanding the concept

We use the formula of magnetic field due to a long straight wire at perpendicular distance from the axis to find the current in the wire.

Formula:

B=渭0i2蟺搁

03

Calculate the current in the wire

The magnitude of magnetic field due to a long straight wire at perpendicular distance from axis is given by

B=渭0i2蟺R

WhereRis the distance from the axis of the wire and渭ois the permeability of the free space,iis the current flowing through the wire.

Solving for the current we get

i=2蟺RB渭0

localid="1663019175921" R=88cm=0.88m,B=7.30渭T=7.30脳10-6T,渭0=1.26脳10-6T.m/A

i=2蟺0.88m7.30脳10-6T4蟺脳10-7T.m/A

i=32.1A

the current in the wire is32.1A.

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