91影视

It is given that,

1. Weight of the passenger is W=660kg
2. The height through which the lift is raised is d=150m
3. The time taken by the lift to raise is 60.0s .
4. The speed of the lift is constant.

The problem is based on Newton鈥檚 second law of motion which states that the rate of change of momentum of a body is equal in both magnitude and direction of the force acting on it.Find the velocity of the lift from its displacement and time. Then applying Newton鈥檚 second law, find the net force acting on it. From these two values, find the average power required of the force making the lift, using the corresponding formula.

Formulae:

$$\begin{gathered} P=Fv \\ {F}_{net}=0 \end{gathered}$$

Where,

$F_{net}$Is net force,v is velocity and Pis the power.

The velocity of the lift is,

$$\begin{gathered} v=\frac{150}{60} \\ v=2.5\mathrm{m}/\mathrm{s} \end{gathered}$$

The speed of the lift is constant, its acceleration is zero, and net force acting on it is weight of passengers.

$F=100\mathrm{W}$

$=100\left(660\right)$

$F=6.6脳{10}^4\mathrm{N}$

Now,

$$\begin{gathered} P=Fv \\ P=6.6脳{10}^4\left(2.5\right) \\ =1.65脳{10}^5\mathrm{W} \end{gathered}$$

Therefore, the average power required of the force making the lift is$1.65脳{10}^5\mathrm{W}$.