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Chapter 7: Q23P (page 172)

In Fig. 7-32, a constant force F鈫�aof magnitude 82.0Nis applied to a 3.00kgshoe box at angle蠒=50.0鈭�, causing the box to move up a frictionless ramp at constant speed. How much work is done on the box by F鈫�awhen the box has moved through vertical distance h=0.150m?

Short Answer

Expert verified

Work done on the box by applied force is 4.41J.

Step by step solution

01

Given data

  1. The applied force is,Fa=82.0N.
  2. Mass of boxis, m=3.0kg.
  3. Vertical height, h=0.150m.
02

Understanding the concept

By using the concept ofchange in kinetic as well as potential energy, we can find the work done during each step.

Formula:

Potential energy,螖PE=mg螖h

03

Calculate the work done on the box

There is no change in kinetic energy as the velocity isthesame. So, the work done is only due to a change in potential energy that is work done by the force of gravity.And it is given by,

W=螖PE=mg螖h

Here螖h is the change in height, which is 0.150m-0=0.150m.

Substitute the values in the above expression, and we get,

W=3kg9.8m/s20.150mW=4.41路1kg路m/s2路m脳1J1kg路m2/s2W=4.41J

Thus, work done on the box by applied force is4.41J .

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